ADM formulation Initial Value Problem data per spacepoint

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SUMMARY

The discussion centers on the ADM formulation of the Initial Value Problem in general relativity, specifically regarding the representation of metric coefficients per spacepoint. It is established that while not all metrics can be transformed into diagonal form, the metric coefficients still yield six values per spacepoint. The forward motion in time is encapsulated within the three data points per spacepoint, as the metric coefficients are functions of time and spatial coordinates. Ultimately, two data points per spacepoint provide insights into the four-dimensional Einstein tensor, with the six partial derivatives of the metric coefficients remaining implicit within these data points.

PREREQUISITES
  • Understanding of ADM formulation in general relativity
  • Familiarity with metric coefficients and their properties
  • Knowledge of the four-dimensional Einstein tensor, ##^{(4)}\mathcal G##
  • Basic concepts of partial derivatives in the context of tensor calculus
NEXT STEPS
  • Study the implications of non-diagonal metrics in ADM formulation
  • Explore the relationship between metric coefficients and their spatial coordinates
  • Investigate the calculation of partial derivatives of metric coefficients
  • Learn about the role of the four-dimensional Einstein tensor in general relativity
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Researchers and students in theoretical physics, particularly those focusing on general relativity and the ADM formulation, as well as mathematicians interested in tensor calculus and its applications in physics.

TerryW
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Homework Statement
See attached screenshot of MTW pp 532/533
Relevant Equations
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I'm having a bit of trouble getting a clear picture of what is going on here, so if anyone can shed any light, it will be greatly appreciated.

1. I can see how the metric coefficients provide the six numbers per spacepoint, but it can't always be possible to transform the metric into a diagonal form can it?

2. The forward motion in time demands one number per spacepoint, which I assume is the value ##\bar t##. How is this 'already willy-nilly' present in the three data per spacepoint? Is it because the various ##g_{ij}## are functions of t, x, y and z so knowing a ##g_{ij}## and its co-ordinates, t follows?

4. Why 'In conclusion...' do we now have TWO data per spacepoint telling us about the ##^{(4)}\mathcal G## and what are they?

5. What has happened to the six ##\frac {\partial g_{ij}}{\partial t} ##?

Regards
TerryW
 

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1. It is not always possible to transform the metric into a diagonal form, as there are some metrics that are already in a diagonal form and some which are not. However, the metric coefficients can still provide the six numbers per space point. 2. The forward motion in time is already present in the three data per spacepoint, as each of the metric coefficients is a function of t, x, y and z. Knowing the values of the metric coefficients and their associated coordinates will allow you to work out the value of t. 4. In conclusion, we now have two data per spacepoint telling us about the ##^{(4)}\mathcal G## - these are the metric coefficients and their associated coordinates.5. The six ##\frac {\partial g_{ij}}{\partial t} ## are still present, but they are now implicit in the two data per spacepoint - each of the coordinates and the associated metric coefficients can be used to calculate the partial derivatives.
 

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