The link to the page that talks about frames doesn't help. I know what a frame is. But I still don't know what you mean when you say things like "you can have more than one light synchronized clock in the same moving frame". That doesn't make sense. If a physical object like a clock is "in" one frame, than it's also in all the others.
A sentence like this one would make sense: "The object has a different shape in frame A than in frame B". But a sentence like this one makes
no sense: "The object is in frame A".
4Newton said:
The drawing fig. 4 (X’0, Z’1, T’3, and T’2) and fig. 5 (X’0, T’0, X’1, T’1, X’2 and T’2) are the lines of objects that are in the same inertial frame (moving in space at a transition equal to one half the speed of light).
Here it seems that you believe that "in the same inertial frame" means "moving with the same velocity", but that would be wrong. When people (other than you) say things like "the velocity of this object in frame A is v" they don't mean that the
object is any more
in frame A than in frame B. They are only specifying in what frame the
velocity is what they say it is, which is absolutely necessary, since the velocity (but not the presence of the object) depends on the choice of frame.
4Newton said:
You have never heard of the Twin paradox?
The "twin paradox" is not a paradox. When SR is used correctly the result is always that the astronaut twin is younger than his brother when he gets back. I have explained why in other posts in this forum. (You should try to understand what I'm trying to explain to you in this thread before you try to understand the twin "paradox").
4Newton said:
X’0 and T’2 are the same in both Fig. 4 and Fig. 5. Fig. 4 is the left view of Fig. 5
"The left view"?! I can only guess what you mean, because you're not making sense here either. I'm guessing that you mean that to an observer who's moving to the left in figure 4 (not drawn), the lines in figure 4 would look like in figure 5. That's not correct. The line X'0---Z'1 should be rotated counterclockwise by the same amount that the line X'0---T'2 has been rotated clockwise. This is absolutely necessary to ensure that the speed of light is the same in both frames (i.e. to both observers).
4Newton said:
The speed of light is constant.
Yes, it's certainly not accelerating. If you mean that it's the same to all different observers, I wonder why it isn't in your diagrams. (If it's c in figure 4, it's more than that in figure 5).
4Newton said:
The relationship of the speed of light to spatial distance is always the same. The relationship of the speed of light to time is always the same.
This is "not even wrong". (It's not clear what it means).
4Newton said:
As also demonstrated in previous posts no actions change the Now.
You haven't demonstrated anything.
4Newton said:
All perceived changes are the result of viewpoint and not any change of the above relationship.
I agree with that (if I understand you correctly), but all you've done is to choose an arbitrary observer's viewpoint and refuse to consider what the world looks like to any other observer. How can you talk about different viewpoints when you refuse to even consider the viewpoints of the observers you call "moving".
4Newton said:
You seem unable to overcome you preset thoughts and look at things from a different viewpoint.
That's not true. I'm just not going to abandon a logically consistent viewpoint, completely free from paradoxes and contradictions, for one that isn't.
4Newton said:
I am not sure what you are asking. Maybe the above reply answers you question.
No, it didn't. The reason I'm asking is that this is the most important concept in all of relativity (the one you need to understand to understand all the "paradoxes") and you don't seem to understand it.
I will ask the question again, in a different way. This time I have interpreted your figure 5 as representing the viewpoint of an observer who's moving to the left with speed v in figure 4, as the events in figure 4 occur.
Let's call the observer whose world line is the left vertical line in figure 4 "A" and the observer who's moving to the left in figure 4 (world line not drawn) "B". Suppose that observer A chooses to use the event at the lower left corner of figure 4 (where the vertical and the horizontal lines meet) as the origin of both space and time coordinates. Also suppose that B uses coordinates such that he is at x=0 all the time, and has t=0 when he passes the vertical line (in figure 4) that is the origin of spatial coordinates to A.
I would like to know which of these statements about figure 5 that you agree with, and which you disagree with.
1. The world line of observer B is a vertical line touching (T'0,X'0).
2. The world line of observer A is the line from (T'0,X'0) to (T'2,X'2).
3. Observer B's time axis (events with spatial coordinate 0 in frame B) is a vertical line touching (T'0,X'0).
4. Observer A's time axis (events with spatial coordinate 0 in frame A) is the line from (T'0,X'0) to (T'2,X'2), i.e. a line through (T'0,X'0) with slope 1/v.
5. Observer B's spatial axis (events with time coordinate 0 in frame B) is the horizontal line drawn in the figure.
6. Observer A's spatial axis (events with time coordinate 0 in frame A) is a line through (T'0,X'0) with slope v.