Airplane propeller and plane's velocity relative to the ground.

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SUMMARY

The discussion focuses on calculating the speed of a point on the tip of an airplane propeller, rotating at 2200 revolutions per minute (rev/min) with a radius of 1.5 meters, while the airplane flies at 550 kilometers per hour (km/h) relative to the ground. For part a, the speed relative to the pilot is determined using the formula v = w × r, resulting in 345.57 m/s. For part b, the speed as seen by an observer on the ground requires the application of the Pythagorean theorem to combine the perpendicular velocities of the propeller tip and the airplane.

PREREQUISITES
  • Understanding of angular velocity and linear velocity
  • Familiarity with unit conversions (rev/min to m/s, km/h to m/s)
  • Knowledge of vector addition and Pythagorean theorem
  • Basic principles of rotational motion
NEXT STEPS
  • Learn about angular velocity calculations in rotational dynamics
  • Study vector addition in physics, particularly for perpendicular vectors
  • Explore unit conversion techniques for speed measurements
  • Investigate the principles of propeller mechanics and aerodynamics
USEFUL FOR

Aerospace engineers, physics students, and anyone interested in understanding the dynamics of airplane propulsion and velocity calculations.

rosstheboss23
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[SOLVED] Airplane propeller and plane's velocity relative to the ground.

Homework Statement


An airplane propeller rotates at 2200 rev/min while the airplane flies at a speed of 550 km/h relative to the ground. The plane's velocity is parallel to the propeller's axis of rotation.
Part a) What is the speed of a point on the tip of the propeller, at radius 1.5 m, as seen by the pilot?

Part b) What is the speed of a point on the tip of the propeller, at radius 1.5 m, as seen by an observer on the ground?

Homework Equations


v=w times r
v=w times r times sin delta



The Attempt at a Solution


I got part a asking speed relative to pilot by converting 2200rev/min to m/s, but part b has me stuck...I don't know if I am missing an equation that I could possibly use but I tried to convert the speed relative to ground to m/s and add it to the 345.57m/s I got as the answer for part a.
 
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rosstheboss23 said:

Homework Statement


An airplane propeller rotates at 2200 rev/min while the airplane flies at a speed of 550 km/h relative to the ground. The plane's velocity is parallel to the propeller's axis of rotation.
Part a) What is the speed of a point on the tip of the propeller, at radius 1.5 m, as seen by the pilot?

Part b) What is the speed of a point on the tip of the propeller, at radius 1.5 m, as seen by an observer on the ground?

Homework Equations


v=w times r
v=w times r times sin delta

The Attempt at a Solution


I got part a asking speed relative to pilot by converting 2200rev/min to m/s, but part b has me stuck...I don't know if I am missing an equation that I could possibly use but I tried to convert the speed relative to ground to m/s and add it to the 345.57m/s I got as the answer for part a.
Notice that the linear velocity of the propeller tip is perpendicular to the velocity of the plane.
 
Remembering that how would I relate 550km/hr to the speed seen by the pilot that is what has me confused. It should form a 90 degree angle and be the same as I calculated in a, but that doesn't work...I tried v= w times r times sin delta and it didn't work.
 
rosstheboss23 said:
Remembering that how would I relate 550km/hr to the speed seen by the pilot that is what has me confused. It should form a 90 degree angle and be the same as I calculated in a, but that doesn't work...I tried v= w times r times sin delta and it didn't work.
The speed is the magnitude of the resultant velocity. How do you normally find the magnitude of two perpendicular vectors?
 
Oh...now I understand this. I would use pythagorean's theorem to get the resultant velocity. Thanks I appreciate your help.
 
rosstheboss23 said:
Oh...now I understand this. I would use pythagorean's theorem to get the resultant velocity. Thanks I appreciate your help.
Correct! No problem :smile:
 

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