Alcubierre Metric: York Time Cause and Effect

MattRob
Messages
208
Reaction score
29
So, there's a paper here that I'm a bit confused about. On pages 3 and 4, it talks about energy density magnitude and York time.

What I'm a bit confused about, is in the article that linked me to it, the scientist makes mention of eventually generating negative vacuum energy.

However, from reading the paper, I get the impression that the energy density distribution is the cause: That by creating this toroidal geomoetry of energy density, the York time magnitudes will come as a result. At least, that's the impression the paper gives me.

To quote:
... While this line of reason seems to resolve the paradox, it also suggests that the York Time may not be the driving phenomenon, rather a secondary result. In this physical explanation of the mathematics, the York Time might be thought of as perhaps a Doppler strain on space as this spherical region is propelled through space. A pedestrian analog to use to help envision this concept would be to consider the hydrodynamic pressure gradients that form around a spherical body moving through a fluid – the front hemisphere has a high pressure region while the rear hemisphere has a low pressure region. Analogously, the warp bubble traveling through space-time causes space to pile up (contract) in front of the bubble, and stretch out (expand) behind the bubble.

But if that's the case, then why is generating negative vacuum energy necessary: Is that just to better understand negative York time, or is it necessary? Which causes which? Does the York time geometry result in the energy density distribution, or does the energy density distribution cause the York time geometry?

Because while it seems to really heavily indicate that the toroidal placement of energy density causes the York time curvature, I'm left puzzled as to why it would be necessary, then, to invoke negative energy density to generate this "warp field"?

Because if the York time is a result of the toroidal energy density, then wouldn't negative energy density be unnecessary to generate the "warp field", but rather come as a consequence of generating it with positive energy density?
 
Physics news on Phys.org
Harold White's work is not generally accepted in the GR community. Matt Visser and many others have published multiple different proofs that negative energy is required to create any warp drive or any stable wormhole.
 
  • Informative
Likes pinball1970
MattRob said:
So, there's a paper here that I'm a bit confused about. On pages 3 and 4, it talks about energy density magnitude and York time.
In the pdf at the bottom of this link, it states everywhere that negative energy is required. How do conclude it says otherwise?
 
Thread 'Can this experiment break Lorentz symmetry?'
1. The Big Idea: According to Einstein’s relativity, all motion is relative. You can’t tell if you’re moving at a constant velocity without looking outside. But what if there is a universal “rest frame” (like the old idea of the “ether”)? This experiment tries to find out by looking for tiny, directional differences in how objects move inside a sealed box. 2. How It Works: The Two-Stage Process Imagine a perfectly isolated spacecraft (our lab) moving through space at some unknown speed V...
Does the speed of light change in a gravitational field depending on whether the direction of travel is parallel to the field, or perpendicular to the field? And is it the same in both directions at each orientation? This question could be answered experimentally to some degree of accuracy. Experiment design: Place two identical clocks A and B on the circumference of a wheel at opposite ends of the diameter of length L. The wheel is positioned upright, i.e., perpendicular to the ground...
According to the General Theory of Relativity, time does not pass on a black hole, which means that processes they don't work either. As the object becomes heavier, the speed of matter falling on it for an observer on Earth will first increase, and then slow down, due to the effect of time dilation. And then it will stop altogether. As a result, we will not get a black hole, since the critical mass will not be reached. Although the object will continue to attract matter, it will not be a...
Back
Top