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1. The problem statement, all variables and given/known data

Many modern watches operate based on a small quartz tuning fork which transduces a mechanical oscillation into an electrical signal. The frequency of the tuning fork is

inversely proportional to sqrt(l), withlbeing the length of the fork. If the watch keeps perfect time at 20°C, what is the fractional gain or less in time for a quartz tuning fork that is 6mm long at:

(a) 0°C

(b) 30°C

Hint: try working this out algebraically. The changes are small and prone to rounding issues.

α= 0.59 × 10_{Quartz}^{-6}/°C

2. Relevant equations

Not sure if the following equations are useful, but my topic of study right now is based on thermal expansion, as well as calculations based on heat energy (Q = mcΔT).

ΔL = αL(linear thermal expansion)_{0}ΔT

If a body has length L_{0}at temperatureT, then its length_{0}Lat a temperatureT = T_{0}+ ΔT is:

L = L_{0}+ ΔL = L_{0}+ αL_{0}ΔT = L_{0}(1 + αΔT)

Q = mcΔT

3. The attempt at a solution

This question appears to me on a topic that I haven't touched so far in my Physics class; however, I know that the topics I am studying is interconnected with this question somehow. From what I read from the question, I concluded thatfrequency = 1/√lengthbut I don't know how to incorporate that into an equation in which I can find a "ratio." I am stuck here and do not know how to further approach this problem.

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# Homework Help: Algebra - Quartz Tuning Fork Watch

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