All integrable functions are continuous?

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The discussion centers on the relationship between continuity, differentiability, and integrability of functions. It clarifies that while all differentiable functions are integrable due to their continuity, not all integrable functions are continuous, with piecewise functions serving as counter-examples. The assertion that all integrable functions are differentiable is also deemed false, as it follows from the previous points. The conversation highlights the importance of understanding definitions and properties related to these concepts. Overall, the thread emphasizes the nuances of function behavior in calculus.
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I have a couple of true and false questions I'm looking at in order to review for my final next Friday (not tomorrow). First, when someone says that a function is continuous does that mean continuous on its domain or continuous at all reals? For example, tan(x) is continuous on its domain but not continuous at all reals so is tan(x) a continuous function?

1. All differentiable functions are integrable.
True because all differentiable functions are continuous and by FTC all continuous functions are integrable.

2. All integrable functions are continuous.
This doesn't follow from the FTC, but I'm having trouble thinking of a counter-example. I looked around on the web and saw a couple people say that this is false, but never explain why. Can you integrate piecewise functions? If so then I can think of an easy counter-example. We've never talked about doing so in class.

3. All integrable functions are differentiable.
Even though 1 is true this doesn't follow from it. Same difficulty as 2.
 
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A continuous function is continuous on its domain. Your intuition is right about 2 (not all integrable functions are continuous). Go back to the definitions to confirm this. By 1 and 2, the answer to 3 follows.
 
you can integrate piecewise functions by splitting the integral. ie

$\begin{array}{l}<br /> f\left( x \right) = \left\{ \begin{array}{l}<br /> 5 \Leftarrow x &lt; 0 \\ <br /> - 5 \Leftarrow x \ge 0 \\ <br /> \end{array} \right. \\ <br /> \int_{ - 1}^1 {f\left( x \right)dx} = \int_{ - 1}^0 {f\left( x \right)dx} + \int_0^1 {f\left( x \right)dx} = \left[ { - 5x} \right]_{ - 1}^0 + \left[ {5x} \right]_0^1 = 0 \\ <br /> \end{array}$<br />
 
Are all functions that can be differentiated, integratable? It makes sense to think this, but what about something like y = x^x, you can diffentiate implictly, using logs.
lny = xlnx
then diffentiate this, but can y = x^x be integrated. I can't see how but I might be wrong.
 
Are all functions that can be differentiated, integratable?

See section 1 in the original post.
 
Are you talking in the generality of riemann sums?
 
Question: A clock's minute hand has length 4 and its hour hand has length 3. What is the distance between the tips at the moment when it is increasing most rapidly?(Putnam Exam Question) Answer: Making assumption that both the hands moves at constant angular velocities, the answer is ## \sqrt{7} .## But don't you think this assumption is somewhat doubtful and wrong?

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