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Alpha particle in gold foil scatering experiment

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  1. Mar 8, 2015 #1
    1. The problem statement, all variables and given/known data
    How close does the alpha particle gets to the nucleus in gold foil scatering experiment?


    2. Relevant equations
    Ek = 2.0 MeV
    W=F delta x
    F=(kq1q2)/r^2
    W=(kq1q2)/r
    E=W=(kq1q2)/r
    3. The attempt at a solution
    E= (k(79)(2) e^2)/r
    2.0MeV= (k(158)e^2)/r
    2,000,000 eV = 8.99 Wm^2 c^-2 ((158) e^2) / r
    2,000,000 eV convert by multiplying by 1.6 x 10^-19 J/ eV
    r = 8.99 x10^ 9 Nm^2/c^2 (158) (1.6x 10^-19 c)^2 / 2,000,000 ev
    r = 1.13 x 10^-13

    I made somewhere mistake as the answer should be around 4 not 1.13 .
    Any input appreciated
     
  2. jcsd
  3. Mar 8, 2015 #2

    rude man

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    Homework Helper
    Gold Member

    How about dividing by Joules instead of eV in your last equation?
     
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