Alpha particle touching Gold nucleus

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SUMMARY

The discussion centers on calculating the minimum kinetic energy required for an alpha particle to touch a gold nucleus, given the nucleus radius of 6.47 femtometers (fm) and the alpha particle radius of 2.36 fm. The relevant equation used is the electrostatic potential energy formula, Ue=(kq1q2)/r, where q1 is the charge of the alpha particle (2) and q2 is the charge of the gold nucleus (79). The calculated kinetic energy of approximately 3E45 eV is deemed excessively high, indicating a potential error in the application of the formula or unit conversion.

PREREQUISITES
  • Understanding of electrostatic potential energy and its relation to kinetic energy.
  • Familiarity with the concept of nuclear radii in femtometers.
  • Knowledge of charge units and their significance in nuclear physics.
  • Basic proficiency in using the Coulomb's law formula.
NEXT STEPS
  • Review the principles of Coulomb's law and its application in nuclear physics.
  • Study the conversion of energy units, particularly electronvolts (eV) to joules.
  • Investigate the concept of nuclear forces and their impact on particle interactions.
  • Explore advanced topics in quantum mechanics related to particle collisions.
USEFUL FOR

This discussion is beneficial for physics students, educators, and researchers focusing on nuclear physics, particularly those studying particle interactions and energy calculations in nuclear collisions.

kraigandrews
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Homework Statement


If the radius of the gold nucleus is 6.47 fm, and the radius of the α particle is 2.36 fm, then what is the minimum required kinetic energy for the α particle if we want the two nuclear surfaces to touch in a head-on collision?

Homework Equations


Ue=(kq1q2)/r


The Attempt at a Solution


so using Ue=KE
q1=2
q2=79

then it should be straightforward plug and chug, however the KE this yields is very high, around 3E45 eV this cannot be right, what am I doing wrong?
 
Physics news on Phys.org
The alpha-particle moves from infinity to a distance of ralpha + rau femtometres from the centre of the gold nucleus.
 
kraigandrews said:

The Attempt at a Solution


so using Ue=KE
q1=2
q2=79



what is the unit of q?

ehild
 

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