- #1
P51Mustang
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Moved from a technical math section, so missing the template
So i have an equation problem that i need to find the 2nd derivative of, but my understanding of the chain rule is not the best. I tried working it out but i don't know if i did it correctly.
i was given the equation y=4(x2+5x)3
So to take the first derivative, i started off by using the chain rule as i understand it and simplified it to:
y'=[12(x2+5x)2][2x+5]
This is where i start to get confused. I don't really know for certain how I am supposed to take the 2nd derivative of that. I assumed that i needed to actually multiply and simplify the first derivative to take the 2nd, but i don't know if what i did or what i got was correct.
I simplified the first derivative and ended up with: y'=24x5+60x4+1200x3+3000x2
Then i calculated the 2nd derivative and got: y''=120x4+240x3+3600x2+6000x
Would this be correct?
i was given the equation y=4(x2+5x)3
So to take the first derivative, i started off by using the chain rule as i understand it and simplified it to:
y'=[12(x2+5x)2][2x+5]
This is where i start to get confused. I don't really know for certain how I am supposed to take the 2nd derivative of that. I assumed that i needed to actually multiply and simplify the first derivative to take the 2nd, but i don't know if what i did or what i got was correct.
I simplified the first derivative and ended up with: y'=24x5+60x4+1200x3+3000x2
Then i calculated the 2nd derivative and got: y''=120x4+240x3+3600x2+6000x
Would this be correct?