a) A 50 g ice cube can slide without friction up and down a 30 degree slope. The ice cube is pressed against a spring at the bottom of the slope, compressing the spring 10 cm. The spring constant is 25 N/m. When the ice cube is released, what total distance will it travel up the slope before reversing direction?
b) The ice cube is replaced by a 50 g plastic cube whose coefficient of kinetic friction is 0.20. How far will the plastic cube travel up the slope?
change in thermal energy= (force of kinetic friction)*(displacement)
The Attempt at a Solution
I got part a, and I want to make sure I am doing part b correctly.
Here's what I did.
Fk= mgcostheta * coefficient of friction
Fk= (.05kg)(9.80)(cos30)(.20)=.085 N
change in thermal energy= Fk* distance covered up slope (d)
change in thermal energy = .085 * d
I called y the final height so y=dsin30
Kf + Uf + change in thermal energy = Ki + Ui
(.05kg)(9.80)(dsin30) + (.085d) = (.5)(25 N/m)(.1m)^2
d= .379 m = 37.9 cm