Amount of power consumed by a non linear light bulb

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Discussion Overview

The discussion revolves around calculating the power consumed by a nonlinear light bulb connected in series with a resistor and a battery. Participants explore the relationship between voltage and current as depicted in provided figures, and the implications for power consumption in the circuit.

Discussion Character

  • Homework-related
  • Mathematical reasoning

Main Points Raised

  • One participant states that the sum of the voltage across the bulb and the voltage across the resistor must equal the total voltage from the battery.
  • Another participant suggests using the current through the resistor to determine the voltage across the bulb, indicating a method to find the current that satisfies the voltage equation.
  • There is a calculation presented where one participant claims to have found the power consumed by the bulb and the resistor based on a specific current and voltage.
  • A later reply reiterates the power calculations for both the bulb and the resistor, but also requests that answers not be provided directly to students on homework assignments.

Areas of Agreement / Disagreement

Participants appear to agree on the method of calculating power based on the voltage and current relationships, but there is no consensus on the final values or the appropriateness of providing direct answers to homework questions.

Contextual Notes

Participants reference specific figures that are not included in the text, which may limit understanding of the discussed relationships. The discussion also hinges on the interpretation of the nonlinear characteristics of the bulb, which may not be fully resolved.

Who May Find This Useful

Students working on circuit analysis, particularly those dealing with nonlinear components and power calculations in series circuits.

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Homework Statement



figure 1 shows the relation ship between voltage and current when voltage is applied o a certan light bulb. Next as shown in figure 2, the bulb os connected n series with a 12V battery and 5Ω resitor.
Figure 1
http://imageshack.us/photo/my-images/585/imagnecir.png/
http://imageshack.us/photo/my-images/585/imagnecir.png
Fgure 2
http://imageshack.us/photo/my-images/401/imagnecir2.png/
http://imageshack.us/photo/my-images/401/imagnecir2.png

what is the amount of power consumend by the light bulb?thanks
 
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The one thing you know is that the (voltage across the bulb) + (voltage across the 5ohm resistor) =12V
The voltage across the resistor is always going to be Ix5... look up the current axis for the bulb and find what current will give a (voltage across the bulb) + Ix5 =12 (it works out quite nicely)
 
ok. thanks
 
did you get 2A x 2V = 4W for the bulb and 2A x 10V = 20W for the resistor?
 
yes. thanks
 
truesearch said:
did you get 2A x 2V = 4W for the bulb and 2A x 10V = 20W for the resistor?

Please do not give answers to students on their homework assignments.
 

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