I'm still a little confused about Bohmian mechanics and probabilities, in the case of spin-1/2.
Empirically, we have the following situation:
- You prepare a beam of electrons and filter out only those that are spin-up in the direction [itex]\hat{a}[/itex] (by sending them through a Stern-Gerlach device and only considering those that deflect in a particular direction).
- You perform a second filtering, and filter out those that are spin-up in the direction [itex]\hat{b}[/itex].
- The fraction of those who pass both filters is given by: [itex]cos^2(\frac{\theta}{2})[/itex] where [itex]\theta[/itex] is the angle between [itex]\hat{a}[/itex] and [itex]\hat{b}[/itex]. This can also be written, using a trigonometric identity as: [itex]\frac{1}{2}(1+cos(\theta)) = \frac{1}{2}(1+ \hat{a} \cdot \hat{b})[/itex], if [itex]\hat{a}[/itex] and [itex]\hat{b}[/itex] are unit vectors.
Now, we try to explain this using a local deterministic hidden-variable theory (we'll get to the nonlocal version in a moment). That means we assume that there is a variable [itex]\lambda[/itex] attached to each electron, and it's value is distributed according to some probability distribution [itex]P(\lambda)[/itex], and this variable determines whether the electron passes the second filter. Then to agree with predictions, the set [itex]V_{\hat{b}}[/itex] of all values of [itex]\lambda[/itex] such that the electron will pass the second filter must have a measure equal to [itex]\frac{1}{2}(1+ \hat{a} \cdot \hat{b})[/itex]. We can go through a Bell-type argument to show that there is no probability distribution [itex]P(\lambda)[/itex] that can simultaneously give this measure to each set [itex]V_{\hat{b}}[/itex] for all possible values of [itex]\hat{b}[/itex]. (We can actually do better than that, and find three values of [itex]\hat{b}[/itex], and prove that there is no probability distribution that works for those three values.)
So my question is: how does allowing nonlocal interactions change this story? I think I just need to work this out myself. Presumably, allowing nonlocal interactions makes the problems of the impossible probability distribution disappear, but at the moment, I'm not sure I can put together why.