I'm still a little confused about Bohmian mechanics and probabilities, in the case of spin-1/2.
Empirically, we have the following situation:
- You prepare a beam of electrons and filter out only those that are spin-up in the direction \hat{a} (by sending them through a Stern-Gerlach device and only considering those that deflect in a particular direction).
- You perform a second filtering, and filter out those that are spin-up in the direction \hat{b}.
- The fraction of those who pass both filters is given by: cos^2(\frac{\theta}{2}) where \theta is the angle between \hat{a} and \hat{b}. This can also be written, using a trigonometric identity as: \frac{1}{2}(1+cos(\theta)) = \frac{1}{2}(1+ \hat{a} \cdot \hat{b}), if \hat{a} and \hat{b} are unit vectors.
Now, we try to explain this using a local deterministic hidden-variable theory (we'll get to the nonlocal version in a moment). That means we assume that there is a variable \lambda attached to each electron, and it's value is distributed according to some probability distribution P(\lambda), and this variable determines whether the electron passes the second filter. Then to agree with predictions, the set V_{\hat{b}} of all values of \lambda such that the electron will pass the second filter must have a measure equal to \frac{1}{2}(1+ \hat{a} \cdot \hat{b}). We can go through a Bell-type argument to show that there is no probability distribution P(\lambda) that can simultaneously give this measure to each set V_{\hat{b}} for all possible values of \hat{b}. (We can actually do better than that, and find three values of \hat{b}, and prove that there is no probability distribution that works for those three values.)
So my question is: how does allowing nonlocal interactions change this story? I think I just need to work this out myself. Presumably, allowing nonlocal interactions makes the problems of the impossible probability distribution disappear, but at the moment, I'm not sure I can put together why.