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An Asteroid is moving along a straight line

  1. Mar 25, 2015 #1
    1. The problem statement, all variables and given/known data
    An asteroid is moving along a straight line. A force acts along the displacement of the asteroid and slows it down. The asteroid has a mass of 4.5*10^4 kg, and the force causes its speed to change from 7100m/s to 5500m/s.
    (a) What is the work done by the force?
    (b) If the asteroid slows down over a distance of 1.8*10^6m, Determine the magnitude of the force.

    2. Relevant equations
    W=F*cos(theta)*s
    F=ma
    instantaneous acceleration = delta(v)/delta(t) as limit of t approaches 0.
    W=KEf-KEo= 1/2MVf^2 - 1/2MVo^2

    3. The attempt at a solution
    First, I looked for the instantaneous acceleration created by the force by subtracting 7100m/s - 5500m/s
    a= 16,000 m/s. This means the force slowed down the asteroid by 1.6*10^4 m/s.
    I multiply 45,000 kg by 16,000 m/s to calculate the force.
    F= 7.2*10^8 N
    I plug this in to my work equation:
    W=7.2*10^8*cos(180)*s

    that's where i'm stuck because I'm not sure what my displacement is.
    I tried the last equation and found initial Kinetic energy as Ke=1/2mv^2
    so: 1/2(4.5*10^4kg)(7100m/s)^2
    = 1.13*10^12
    final kinetic is initial kinetic + work
    1.13*10^12 + Fcos(theta)s

    I feel like I may be over-complicating this question. I feel like i'm close but i'm missing something obvious. Help appreciated!
     
  2. jcsd
  3. Mar 25, 2015 #2

    Orodruin

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    Staff Emeritus
    Science Advisor
    Homework Helper
    Gold Member

    Yes, you are over complicating things. You already have an expression for work in terms of the initial and final kinetic energies, what do you get if you use it? Once you have found the work, how can you compute the force from this?

    Note: Never forget that physical quantities come with units, they are important and without them your results do not hold any meaning. ,ake it a habit to always write them out!
     
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