An electron moving through a uniform magnetic field

[Destroxia]

Homework Statement

An electron moves through a uniform magnetic field given by B = Bx i + (3.68 Bx) j . At a particular instant, the electron has velocity v = (1.88 i +4.86 j) m/s and the magnetic force acting on it is (2.43 × 10-19) N. Find Bx.

Givens

B = [Bx i + (3.68 Bx)]

v = (1.88 + 4.86)

Fb = (2.43 × 10-19) N. Find Bx.

2. Homework Equations

Fb = q(B x V)

The Attempt at a Solution

(2.43 x 10^-19)k = (1.602 x 10^-19) [(Bx i + (3.68Bx) j) x (1.88 i + 4.86 j)

cross product resultant:

(2.43 x 10^-19)k = (1.602 x 10^-19) (-2.06*Bx)k

(2.43 x 10^-19)k = (-3.30 x 10^-19*Bx) k

I don't understand how to solve for the Bx, we haven't learned how to divide vectors, and I can't really pull the Bx out of the k vector as a scalar. How do I solve for the Bx?

 

[haruspex]

Homework Statement

An electron moves through a uniform magnetic field given by B = Bx i + (3.68 Bx) j . At a particular instant, the electron has velocity v = (1.88 i +4.86 j) m/s and the magnetic force acting on it is (2.43 × 10-19) N. Find Bx.

Givens

B = [Bx i + (3.68 Bx)]

v = (1.88 + 4.86)

Fb = (2.43 × 10-19) N. Find Bx.

2. Homework Equations

Fb = q(B x V)

The Attempt at a Solution

(2.43 x 10^-19)k = (1.602 x 10^-19) [(Bx i + (3.68Bx) j) x (1.88 i + 4.86 j)

cross product resultant:

(2.43 x 10^-19)k = (1.602 x 10^-19) (-2.06*Bx)k

(2.43 x 10^-19)k = (-3.30 x 10^-19*Bx) k

I don't understand how to solve for the Bx, we haven't learned how to divide vectors, and I can't really pull the Bx out of the k vector as a scalar. How do I solve for the Bx?

Since the two unit vectors are identical, you can cancel them. But if you want to do it by pure methods, there are two ways: consider magnitudes; take the dot product of each side with something convenient.

 

[BvU]

B_X is not a vector, it is a number with a dimension. The vectors are $\vec v$ and $\vec B = B_X \hat\imath + (3.68\;B_X) \hat\jmath\$.
So check the dimensions (they should be fine) and find the value as you intended to do: by dividing.

 

[haruspex]

B_X is not a vector, it is a number with a dimension. The vectors are $\vec v$ and $\vec B = B_X \hat\imath + (3.68\;B_X) \hat\jmath\$.
So check the dimensions (they should be fine) and find the value as you intended to do: by dividing.

I believe Ryan is referring to the two k vectors.

 

[collinsmark]

Hello RyanTAsher,

Before I go through the math (privately on my own), could you help clear up a few ambiguities?

I'm assuming that the x in B_x is a subscript and not a variable. (In other words, I'm assuming that \vec B is uniform and not a function of x.) Is that correct?

Are you sure about \vec F = q \left( \vec B \times \vec v \right)? Is that correct or is something backwards?

(Also, don't forget that the charge of an electron is negative. i.e., q = -e)

In the initial problem statement, the force was given as (2.43 × 10-19) N with no direction specified. Later, you tacked on a \hat k. I'm just wondering if the original problem statement had the \hat k in it, or if the (2.43 × 10-19) N figure was meant to be magnitude only without specifying a direction. [Edit: Going through the math, I realize that the force must be along the z axis. But ultimately, one still needs to determine if the force is pointing in the positive or negative direction of the axis.]

 

[BvU]

@Haru: of course, naive of me to overlook that; thanks!
@CM: well pointed out. But now the wrong expression is appearing twice already in this thread (shudder) ...

@RTA: you're in good hands ! Bedtime for me. Good luck. And dividing out vectors is like dividing out Yuzzamatuzzes: if Z_fluff Yuzzamatuzzes = 2.5 Yuzzamatuzzes, then you can be sure Z_fluff = 2.5. It's a property of multiplication, not a property of Yuzzamatuzzes. There is only one snag to beware of: things go awry if Yuzzamatuzz = 0, because then you can't "divide them out" any more. (With thanks to dr. Seuss)

 

[Destroxia]

Hello RyanTAsher,

Before I go through the math (privately on my own), could you help clear up a few ambiguities?

I'm assuming that the x in B_x is a subscript and not a variable. (In other words, I'm assuming that \vec B is uniform and not a function of x.) Is that correct?

Are you sure about \vec F = q \left( \vec B \times \vec v \right)? Is that correct or is something backwards?
I'm just wondering if the original problem statement had the \hat k in it, or if the (2.43 × 10-19) N figure was meant to be magnitude only without specifying a direction.

Yes, the Bx is a B with subscript x, B_x, and the force value did have the \hat k with it. Sorry for the confusion. I am pretty positive about the \vec F = q \left( \vec B \times \vec v \right) as that is what it says in my textbook.

 

[BvU]

The Lorentz force is definitely $$
\vec F = q\, \left (\vec E + \vec v \times \vec B \right )
$$no matter what your textbook says.