An organ pipe is 84 cm long and at a temperature of 20 degrees C.

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Homework Help Overview

The problem involves calculating the fundamental frequency of an organ pipe that is 84 cm long and closed at one end, with the temperature given as 20 degrees Celsius. The context is within the subject area of acoustics and wave behavior in closed pipes.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • Participants discuss the relationship between the length of the pipe and the wavelength, with some suggesting the use of diagrams to visualize nodes and antinodes. There are questions regarding the relevance of specific equations related to frequency and harmonics.

Discussion Status

The discussion includes attempts to clarify concepts related to the fundamental frequency of the pipe. Some participants express confusion about the equations and their components, while others provide hints and guidance without revealing complete solutions. There is an indication of progress as one participant expresses understanding after engaging with the discussion.

Contextual Notes

Participants mention preparing for a physics final, which may influence their level of understanding and the urgency of their inquiries. There is also a reference to the speed of sound at the given temperature, which is relevant to the problem but not fully explored in the discussion.

JohnnyB212
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Homework Statement



An organ pipe is 84 cm long and at a temperature of 20 degrees C. What is the fundamental (in Hertz) if the pipe is closed at one end?


Homework Equations



To best honest, I'm not really to sure where to start. Can anyone please help? Start me off?

Thanks in advance!
 
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Start off drawing a picture! nodes and anti-nodes this will show you the ratio of length of the pipe to the wave length! If you need more help just say so I am going to use this as an exercise to review harmonics so i will find the answer.
 
Mthees08 said:
Start off drawing a picture! nodes and anti-nodes this will show you the ratio of length of the pipe to the wave length! If you need more help just say so I am going to use this as an exercise to review harmonics so i will find the answer.


The picture alone doesn't really help me much though. :confused:
 
well if you draw it you see you have 1 node 1 antinode which means the length of the pipe is 1/4 the wavelength the speed of sound at 20C is 344 m/s freq=v/wavelength. Thats really all I can say without telling you the answer lol
 
lol Gosh I'm sorry, I'm still confused, Iv'e been working on this stuff all day preparing for my physics final tomorrow, and I'm extremely confused.

does the equation Fn = n * (v / 4L) have anything to do with it?
 
JohnnyB212 said:
lol Gosh I'm sorry, I'm still confused, Iv'e been working on this stuff all day preparing for my physics final tomorrow, and I'm extremely confused.

does the equation Fn = n * (v / 4L) have anything to do with it?

Don't worry about being confused, it can get that way especially when you start adding ns and random variables in. If you look that is the equation I gave you, with 2 ns in it, which if I remember correctly correspond to the number of nodes maybe? I am not sure, however I believe they are there simply to confuse you. They might be the harmonics of a pipe,

Fn = (n+1)*(V/4L) is the relation that I would use to describe number of nodes to the frequency of a pipe with 1 end open So if you explain n I might be able to help explain that equation but it is not one I am familiar with.

Hint: Closed ends have nodes, open ends have anti-nodes
 
OH! I got it!

Since there was 1 node and 1 antinode, I assumed it canceled out, I simply put in

344 / (4 * .84)

And it was correct lol, Thanks for your help! I appreciate this!
 

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