eljose
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Let be the Hamitonian of a particle with mass m in the form:
H=\frac{-\hbar^{2}}{2m}D^{2}\phi(x)+V(x)\phi(x)
then the RH is equivalent to prove that exist a real potential V(x) of the Hamiltonian so that the values E_n H\phi=E_{n}\phi satisfy the equation \zeta(1/2+iE_{n})=0 that is the roots of the Riemann zeta function are the Energies of the system...
you only need to prove that V(x) is real,so the H will be self-adjoint,we can write the solution of the problem (approximately) by the wave function:
\phi=e^{iS/\hbar} with S=\int(2mE_{n}-2mV(x))^{0.5}dx
with that you can substituting into Schroedinguer equation get a differential equation of second order for V(x) F(x,V(x),DV(x),D^{2}V(x),E_{n})=0
the key is that you needn,t solve the equation you only have to prove that the potential will be real by knowing that energies satisfy \zeta(1/2+iE_{n})=0 i will try to submit to some math teacher to see if i can do my PhD in math-physics in this matter...
H=\frac{-\hbar^{2}}{2m}D^{2}\phi(x)+V(x)\phi(x)
then the RH is equivalent to prove that exist a real potential V(x) of the Hamiltonian so that the values E_n H\phi=E_{n}\phi satisfy the equation \zeta(1/2+iE_{n})=0 that is the roots of the Riemann zeta function are the Energies of the system...
you only need to prove that V(x) is real,so the H will be self-adjoint,we can write the solution of the problem (approximately) by the wave function:
\phi=e^{iS/\hbar} with S=\int(2mE_{n}-2mV(x))^{0.5}dx
with that you can substituting into Schroedinguer equation get a differential equation of second order for V(x) F(x,V(x),DV(x),D^{2}V(x),E_{n})=0
the key is that you needn,t solve the equation you only have to prove that the potential will be real by knowing that energies satisfy \zeta(1/2+iE_{n})=0 i will try to submit to some math teacher to see if i can do my PhD in math-physics in this matter...