Analysis of Lorentz Force in Semiconductor

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The discussion focuses on the Lorentz force in N-type and P-type semiconductors under the influence of electric and magnetic fields. In an N-type semiconductor with an electric field in the x-direction and a magnetic field in the z-direction, the Lorentz force acts in the negative y-direction, resulting in a negative Hall constant (R_H = -1/ne). Conversely, for a P-type semiconductor, the Lorentz force acts in the positive y-direction, leading to a positive Hall constant (R_H = 1/pe). The participants confirm the correctness of these relationships, emphasizing the differences between N-type and P-type materials. This analysis highlights the fundamental behavior of charge carriers in semiconductors under electromagnetic influences.
Petar Mali
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I have a few questions about this effect. If I have some semiconductor of N type in which I have electrical field in x direction, and magnetic field in z direction

\vec{E}=E\vec{e}_x

\vec{B}=B\vec{e}_z

Then Lorence force is in the -y direction because in N type of semiconductor n>>p so

F_l=-e\vec{\upsilon_D}x\vec{B}

And for this case Hall constant R_H=-\frac{1}{ne} is negative. Am I right?

And in same case but for P type Lorentz force will be

F_l=e\vec{\upsilon_D}x\vec{B}

so in y direction, and Hall constant

R_H=\frac{1}{pe}?
 
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