1. The problem statement, all variables and given/known data Consider a parallel universe where the laws of nature as we know them are different, and aqueous solutions can have an excess charge. Two beakers are separated 1.20 meters and each contains 0.300 L of an aqueous solution of 6.40 × 10-6 M excess charge. One beaker has a net positive charge, and one beaker has a net negative charge. Calculate the force between the beakers using the formula below, where F is force, ε0 is the permittivity constant and is equal to 8.85 × 10-12 C2/(N·m2)·, q1 is the charge contained in the first beaker, q2 is the charge contained in the second beaker, and r is the distance between the beakers. Note that 1 mole of charge is 96,485 C, and because one of the beakers contains a net negative charge, one q will be negative, and F will be negative. A negative F corresponds to an attractive force. 2. Relevant equations 3. The attempt at a solution I found the charge on the solutions to be to be .1853 and -.1853. I did this by multiplying the molarity by the volume .300L and then 96468 C. After getting those numbers, I plugged into the formula and got an insanely large number for the force, -2.31 x 109. I'm not sure if I'm not understanding the problem or if it is an arithmetic error. Thank you!