Analyzing a Distribution Function

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Homework Help Overview

The problem involves analyzing a distribution function for a real random variable X, with specific values defined for different intervals of x. Participants are tasked with plotting the function and calculating various probabilities related to X.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • Participants discuss plotting the distribution function and express uncertainty regarding the calculations for probabilities, particularly for P(X > 1/2) and P(X < 3). There is an exploration of the relationship between cumulative distribution and probability calculations.

Discussion Status

Some participants have offered guidance on using the cumulative distribution function to find probabilities, while others are attempting to clarify their understanding of the calculations involved. Multiple interpretations of the probability calculations are being explored.

Contextual Notes

Participants are navigating the definitions and properties of probability distributions, including the handling of inequalities and specific values. There is an indication of confusion regarding the correct application of formulas for calculating probabilities.

twoski
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Homework Statement



The distribution function of a real random variable X is given:

F(x) =

0 : x < 0
x/2 : 0 ≤ x < 1
2/3 : 1 ≤ x < 2
11/12 : 2 ≤ x < 3
1 : 3 ≤ x

(a) Plot this distribution function.
(b) What is P( X > 1/2 ) ?
(c) What is P( 2 < X ≤ 4 ) ?
(d) What is P( X < 3 ) ?
(e) What is P( X = 1 ) ?

The Attempt at a Solution



Plotting was easy, but now I'm just unsure of my answers to the others.

P( 2 < X < 4 ) = 1 - 2/3 = 1/3
P( X = 1 ) = 2/3
P( X > 1/2 ) = ? This one confuses me.
P( X < 3 ) = F(0) + F(1) + F(2) ? Not sure if i need to be subtracting something here since this is wrong.
 
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For (b), use the fact that ##P(X > x) = 1 - P(X \le x)##.
 
Ah, so it would essentially be 1 - P(x ≤ 1/2) which translates to 1 - 0.25 = 0.75, right?
 
For question (d) would i just do the opposite of your formula and subtract 1 from P( X >= x )?
 

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