Analyzing Continuity and Differentiability of f(x) at x=1 & x=3

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Homework Help Overview

The discussion revolves around the analysis of continuity and differentiability of a piecewise function defined differently for values of x greater than or equal to 1 and less than 1, specifically at the points x=1 and x=3.

Discussion Character

  • Exploratory, Assumption checking, Conceptual clarification

Approaches and Questions Raised

  • Participants explore the continuity and differentiability of the function at the specified points, with one participant questioning the continuity and differentiability at x=1 based on the limits from both sides. Another participant suggests evaluating the function at x=1 directly.

Discussion Status

The discussion is ongoing, with participants providing different perspectives on the continuity and differentiability at x=1 and x=3. Some guidance has been offered regarding evaluating limits and function values, but there is no explicit consensus reached yet.

Contextual Notes

One participant expresses uncertainty about their arithmetic, indicating potential confusion in the calculations related to the function's behavior at the critical points.

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Homework Statement


f(x) is a piecewise function defined as:

[tex]|x-3| x>=1[/tex]
[tex]\frac{x^2}{4}-\frac{3x}{2}+\frac{13}{4} x<1[/tex]

Discuss the continuity and differentiability of this funtion at x=1 and x=3

Homework Equations





The Attempt at a Solution


At x=3, this function is continuous but not differentiable, being a modulus funtion. But how is is continuous and differentiable at x=1? Putting limit x=1 in the above funtion doesn't give you the same value for both the parts!
 
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Look at the limit as x->1 from both sides of the function and the derivative of the function. What do you get as answers to these four questions?
 
The func is cont. at x=1. Plug in 1 again, in both expression
 
Whoa! I really feel like an idiot now. I messed up the arithemetic.
 

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