Angle Between Chord AB and Tangent at Point B on a Curve

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    Calculus Geometry
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SUMMARY

The discussion focuses on calculating the angle between the chord AB and the tangent at point B on the curve defined by the equation y = (x + 2)^2. The point A is given as (-3, 1), and the normal at this point intersects the curve at B, which is determined to be (-0.5, 2.25). The equation of the normal is identified as 2y = x + 5, while the gradient function of the curve is y' = 2x + 4. The correct angle to be calculated is between the chord AB and the tangent at point B, not the normal.

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  • Understanding of calculus, specifically derivatives and gradients
  • Knowledge of curve equations and their properties
  • Familiarity with the concept of normals and tangents in geometry
  • Ability to solve for points of intersection between curves
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  • Study the derivation of the angle between two lines in coordinate geometry
  • Learn how to find the tangent line to a curve at a given point
  • Explore the concept of chords in relation to curves and their properties
  • Investigate the application of derivatives in determining slopes of curves
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Students studying calculus, particularly those focusing on curve analysis and geometric interpretations of derivatives. This discussion is also beneficial for educators teaching these concepts in a classroom setting.

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Homework Statement



The normal to the curve y= (x + 2)^2 at the point A(-3, 1) meets the curve at B.
Find the angle at B between the curve and chord AB.

2. The attempt at a solution

I found that B is (-0.5, 2.25) and the equation of the normal is 2y= x + 5.
I thought the angle at B between the curve and chord AB was simply the angle between the normal 2y= x + 5 and the gradient function, y'= 2x +4 but the answer is different from what I get.

Any help would be greatful
 
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The angle your are looking is between the chord AB and the tangent of the curve at B.
 

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