Find k so that y - 36x = k is a normal to the curve y = 1 / abs(x-2).
The Attempt at a Solution
My problem is regarding the absolute value. I know that the tangent to the curve must be (-1/36). In the solutions manual, it is said that by knowing the sign of the tangent (i.e. negative) we can know the sign of the absolute value term. How is this possible?