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Angle changes in Relativity (Shooting the Deathstar on a flyby)

  1. Jan 25, 2012 #1
    1. The problem statement, all variables and given/known data
    You are flying the Millenium Falcon and want to shoot the Death Star at the closeest range possible. You fly by the Death star at speed .8c. Just at the time of your closest approach, the death star is 90° from your direction of motion, you shoot the laser gun at it. What is the angle you must set between your direction of motion and the laser gun?


    2. Relevant equations

    cos(θ)=β

    3. The attempt at a solution

    All I did was use the above equation and got that θ=36.87°, which would make sense because the smaller β is, the closer to 90 the angle would become. But this just seems way too easy compared to our other relativity problems, am I doing something wrong?

    Thanks in advance!
     
  2. jcsd
  3. Jan 30, 2012 #2
    Anyone?
     
  4. Feb 2, 2012 #3
    hmmm
     
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