Angle for Impending Motion on Inclined Plane with Attached Blocks

Click For Summary
SUMMARY

The discussion focuses on determining the angle for impending motion of block B, which is resting on block A, with a mass of 12 kg and a coefficient of static friction of 0.20. The user presents their equations but expresses confusion regarding the application of forces in the parallel direction of the ramp. The correct approach involves summing the forces acting on block B in both the parallel and perpendicular directions to accurately assess the impending motion.

PREREQUISITES
  • Understanding of Newton's laws of motion
  • Knowledge of static friction and its coefficient
  • Familiarity with free body diagrams
  • Basic trigonometry for resolving forces
NEXT STEPS
  • Review the principles of static friction in inclined planes
  • Learn how to construct and analyze free body diagrams for multiple bodies
  • Study the equations of motion for systems in equilibrium
  • Explore the effects of varying angles on frictional forces
USEFUL FOR

Students and professionals in physics and engineering, particularly those studying mechanics and inclined plane problems, will benefit from this discussion.

physicsss
Messages
319
Reaction score
0
The 8 kg block A is attached to link AC and rests on the 12-kg block B. Knowing that the coefficient of static friction is 0.20 between all surfaces of contact and neglecting the mass of the link, determine the angle for which motion of block B is impending.

Can someone check my equations and see if they are OK? There's something screwy with the numbers I'm pluggin in so if you can tell me what you should get, I will be grateful. Thanks.

Link to my work: http://img507.imageshack.us/img507/9884/img0801copy2bm.jpg
 
Last edited by a moderator:
Physics news on Phys.org
For impending motion, block B has
Sum of F parallel = - T + 2.5 W_A sin(theta) - mu N - F_1 cos(theta) = 0 .

Somehow you forgot to sum the Forces in that direction?
 
The equation or the pluggin in of the numbers?
 
I didn't see any Sum of Forces equation for block B
in the parallel-to-the-ramp direction (perp to N).
 
Why do I need it?
 
WHAT? That's the direction that the acceleration is to occur in!

The perp-to-ramp component Force Sum is just to get the Friction -
if the ramp was frictionless you wouldn't have needed it at all!
 
That's the last equation labeled translational force...
 
anyone? :-/
 

Similar threads

  • · Replies 27 ·
Replies
27
Views
10K
  • · Replies 7 ·
Replies
7
Views
2K
Replies
3
Views
3K
  • · Replies 5 ·
Replies
5
Views
3K
Replies
12
Views
2K
Replies
18
Views
3K
  • · Replies 16 ·
Replies
16
Views
5K
Replies
5
Views
2K
  • · Replies 7 ·
Replies
7
Views
6K
  • · Replies 13 ·
Replies
13
Views
6K