Angle Ratios: Solving for θ between 0 and 360°

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Homework Help Overview

The problem involves finding all angles θ between 0 and 360° for which the ratio of sin θ to cos θ equals -3. The discussion centers around trigonometric identities and the properties of the tangent function.

Discussion Character

  • Conceptual clarification, Mathematical reasoning, Assumption checking

Approaches and Questions Raised

  • Participants explore the relationship between the sine and cosine functions, particularly through the tangent function. There are attempts to identify the quadrants where tangent is negative and to approximate angles using arctan.

Discussion Status

Participants have provided insights into the properties of tangent and its relation to the problem. There is ongoing exploration of how to derive angles in different quadrants, with some guidance on using arctan and considering angle measures in degrees versus radians.

Contextual Notes

There are mentions of rounding angles and the need to convert between radians and degrees, as well as the implications of angle measures in different quadrants.

chocolatelover
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Hi,

Homework Statement



Find every angle θ between 0 and 360° for which the ratio of sin θ to cos θ is -3.00. (Round your answer to the nearest degree.)

Homework Equations





The Attempt at a Solution



I used the unit circle and took the x value divided by the y value and none of them were -3. Is that how you would do it?

thank you very much
 
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the ratio of sin to cos is the same as [itex]\frac{sin\theta}{cos\theta}[/itex]

Do you know any other trig identity that is the same as that?
 
Thank you very much

That's the same thing as tangent, right? So, I just need to find out which tangent of a degree between 0 and 360 is -3, right? I tried that and everything is either 1 or a decimal number.

Thank you
 
Yes it is the same as tan[itex]\theta[/itex]

Well arctan(3) is a decimal number so just approximate the value.
 
But it has to be equal to 3, right? You could also use Arctan?

Thank you
 
In which quadrants is tan negative? Then the acute angle is arctan(3).
 
Thank you very much

The arctan(3)=1.249. Could you please explain to me how I could find the smallest one and the largest one?

Thank you
 
arctan(3) is the acute angle (A) that lies in the first quadrant. Tan is negative in the 2nd and fourth quadrant. How do you think you would find the angle made by something in the 2nd quadrant?(Hint: the sum of the angles at a point on a straight line is 190)
 
Thank you very much

Isn't 180? So, wouldn't you take 180-1.249?

So the largest angle would be 178.751 and the smallest would be 1.249?

Thank you
 
  • #10
chocolatelover said:
Thank you very much

Isn't 180? So, wouldn't you take 180-1.249?

So the largest angle would be 178.751 and the smallest would be 1.249?

Thank you

1.249 is radians,180 is in degrees...

180 degrees is equivalent to pi radians.

So you would take [itex]\pi -1.249[/itex]
 
  • #11
Thank you

So, in degrees it would be 71.565 or 72 and 108.435 or 108, right?

Thank you very much
 
  • #12
chocolatelover said:
Thank you

So, in degrees it would be 71.565 or 72 and 108.435 or 108, right?

Thank you very much

108.435 would be one answer.

The other answer is in quadrant 4. How would you find the angle made by something in the 4th quadrant? (measuring the angle anti-clockwise and the sum of the angles in a circle is 360)
 
  • #13
Would you just take 360-108?
 
  • #14
chocolatelover said:
Would you just take 360-108?

You would take 360-arctan(3)
 
  • #15
Thank you very much

Regards
 

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