1. The problem statement, all variables and given/known data Consider the potential field V(x, y) which is 0 and -Vo (V0 > 0) respectively in the regions of y greater and less than zero . Let θ and θ' be the angles of incidence and refraction of the particle with the y-axis at the point of incidence as it crosses the x-axis . The ratio sin(θ) / sin(θ ') is given (in terms of Δ = Vo / E) by region1 region2 (a)√(1+2Vο/E) (b)√(1+Vο/E) (c)1+Vο/E (d)1+2Vο/E 2. Relevant equations nsinθ=n'sinθ' sinθ/sinθ'=v/v'[where v=velocity of particle in 1 & v'in 2] 3. The attempt at a solution 1/2mv2=E=1/2mv'2-Vο 1/2mv'2-1/2mv2=Vο (v'2 -v2)/v2=2Vο/mv2 (v'2 /v2 )-1=Vο/(1/2mv2) ∴sinθ'/sinθ=√(1+Vο/E) Which is similar to option b but in question it is sinθ/sinθ'