Angular acceleration, velocity, momentum of a door?

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Haveagoodday said:
you have to use this equation t= θf-θi/wf-wi
you
haruspex said:
wf-wi? Did you mean that?
yes
 
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haruspex said:
What is the are you putting for alpha here? What units do you have for omega?
That one was closest to theta. 90 degrees.
That is the formula for rotational motion...if alpha is a constant
 
Haveagoodday said:
you

yes
I've never seen that equation, and if you were to apply it you would get infinity. w does not change after the force on the door ceases.
 
coffeemanja said:
That one was closest to theta. 90 degrees.
That is the formula for rotational motion...if alpha is a constant
You did not answer either question. What number are you plugging in for alpha, and what units is your number for omega expressed in?
 
haruspex said:
You did not answer either question. What number are you plugging in for alpha, and what units is your number for omega expressed in?
Alpha is 10 rad/s...agh...I see now! Let me redo here...
 
haruspex said:
I've never seen that equation, and if you were to apply it you would get infinity. w does not change after the force on the door ceases.
but i
coffeemanja said:
That one was closest to theta. 90 degrees.
That is the formula for rotational motion...if alpha is a constant
dont forget that you have to use radians instead of degrees. But still it is apparently wrong to use that equation.
 
haruspex said:
I've never seen that equation, and if you were to apply it you would get infinity. w does not change after the force on the door ceases.
well it is kind of like this equation v= dx/dt, and if you rearrange it you get t=dx/dv, and same goes for rotational motion equation w=dθ/dt, at least i think so.
 
Haveagoodday said:
well it is kind of like this equation v= dx/dt, and if you rearrange it you get t=dx/dv.
No, you get dt=dx/v. It is certainly not the case that t=dx/dv.
 
coffeemanja said:
I got 0.795 s
Good, if a little inaccurate. (But why does everyone insist on decimals? What's wrong with ##\pi/4##?
 
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haruspex said:
Good, if a little inaccurate. (But why does everyone insist on decimals? What's wrong with ##\pi/4##?
Wait... It's pi/2. I do not know, may be because we are used to use SI units..
 
coffeemanja said:
Wait... It's pi/2. I do not know, may be because we are used to use SI units..
did you use this equation Θf=Θi+ωi*t+0.5αt^2 ?
 
Haveagoodday said:
did you use this equation Θf=Θi+ωi*t+0.5αt^2 ?
Yes!
 
coffeemanja said:
Yes!
what are the values you put in?
 
Have somebody come to a solution for e)?
 
Haveagoodday said:
Have somebody come to a solution for e)?
I assume you are just looking for a yes/no answer. There's a risk your question might be interpreted as a request for a solution to be posted.
 
Haveagoodday said:
Have somebody come to a solution for e)?
I think somebody posted an answer for part (e).

I don't know if that counts as a solution.
 
Haveagoodday said:
Have somebody come to a solution for e)?
Here's a starting point:

F- Fh = M* a ("h" being in a subscript of F, and "a" being "a" of centre of mass)

I could post whole my work, but I believe It's better for you that you figure it out yourself. But this starting point should be more than enough.
Let me know the result you get in e) and thereby f)
 
e) Fh=F(1-3d/(2L))
f) 2L/3
 
How did you get C) 0.795 s or pi/4
 
jimjames said:
How did you get C) 0.795 s or pi/4
As I said, 0.795 is rather inaccurate.
 
haruspex said:
As I said, 0.795 is rather inaccurate.
It is, but where we study they insist on decimal numbers. It is inaccurate, but the main reason why they do it is so we can use our knowledge about significant digits. You'd be surprised over how many people make silly mistakes on significant digits.
 
StavangerFinest said:
It is, but where we study they insist on decimal numbers. It is inaccurate, but the main reason why they do it is so we can use our knowledge about significant digits. You'd be surprised over how many people make silly mistakes on significant digits.
No, it's more inaccurate than it should be for a three digit decimal. Calculate pi/4.
 
haruspex said:
No, it's more inaccurate than it should be for a three digit decimal. Calculate pi/4.
Oh yeah... 0,785s...Didn't notice that they had nine instead...Sorry, my bad
 
Read the book from page 308 to 314, you will understand the physics not just for one question but for all related questions.
 
Bambisu said:
Read the book from page 308 to 314, you will understand the physics not just for one question but for all related questions.
The thread is two years old. I doubt StavangerFinest is still interested.