Angular Deceleration of Flywheel due to Rotation Motion

  • Thread starter Thread starter thereddevils
  • Start date Start date
  • Tags Tags
    Motion Rotation
Click For Summary

Homework Help Overview

The problem involves calculating the angular deceleration of a flywheel given its initial conditions, including radius, moment of inertia, and initial angular velocity. The flywheel stops after a specified number of revolutions, prompting a discussion on the correct application of kinematic equations in rotational motion.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • Participants discuss the initial angular velocity and the time taken for the flywheel to stop, questioning the assumption of constant angular velocity during deceleration. There are attempts to calculate the average angular speed and its implications for time calculations.

Discussion Status

Participants are exploring different interpretations of the problem, particularly regarding the average speed and its role in determining the time of deceleration. Some guidance has been offered on using average angular speed to find the correct time, but there is still uncertainty among participants about the calculations and concepts involved.

Contextual Notes

There is confusion regarding the relationship between angular displacement and the number of revolutions, as well as the distinction between angular and linear displacement. Participants are also grappling with the implications of non-constant angular velocity on their calculations.

thereddevils
Messages
436
Reaction score
0

Homework Statement



A flywheel of radius 0.20 m with moment of inertia 0.15 kg/m^2 rotates at 180 revolution per minute . A tangential force is applied on the rim of the flywheel and it stops after 12 revolutions.Calculate the angular deceleration .

Homework Equations





The Attempt at a Solution



The initial angular velocity is 18.9 rad/s after conversion. The time taken for 12 revolutions is 4s (since it can rotate 180 times in 60 s , so in 4 s , it can rotate 12 times) . Final angular velocity is 0 .

Using \omega_f=\omega_i+\alpha t

0=18.9+4\alpha

solving this , i got 4.37 sec

but the ans given 2.37 sec, where did i go wrong ?
 
Physics news on Phys.org
thereddevils said:
The time taken for 12 revolutions is 4s (since it can rotate 180 times in 60 s , so in 4 s , it can rotate 12 times) .
That would be true if the angular velocity were constant, but it's not. The wheel is slowing down. Hint: What's the average speed during its acceleration?
 
Doc Al said:
That would be true if the angular velocity were constant, but it's not. The wheel is slowing down. Hint: What's the average speed during its acceleration?

thanks Doctor , so if i take the average velocity , then the time,t =4s would be valid in my calculations ?

a=v/t=(18.9/2)/4=2.37
 
thereddevils said:
thanks Doctor , so if i take the average velocity , then the time,t =4s would be valid in my calculations ?
The thing to do is use the average angular speed to find the correct time. (4s is not correct.) Then you can use your original equation to find the acceleration.
 
Doc Al said:
The thing to do is use the average angular speed to find the correct time. (4s is not correct.) Then you can use your original equation to find the acceleration.

sorry doc , i still don get it .

Is the average simply 18.9/2=9.45 s

Then , i am not sure how to use this to find time .
 
thereddevils said:
sorry doc , i still don get it .

Is the average simply 18.9/2=9.45 s
Yes. (The units are radians/sec.)

Then , i am not sure how to use this to find time .
Use the rotational analog to Distance = Ave Speed X Time
(The "distance" will be the angle in radians.)
 
Doc Al said:
Yes. (The units are radians/sec.)


Use the rotational analog to Distance = Ave Speed X Time
(The "distance" will be the angle in radians.)

thanks i was too hung up with the 180 revolutions as compared to 12 revolutions so a final check ,

the angular displacement is 2pi x 12=75.4 (Initially , i though of 2pi x 0.2 x12 , this would be linear displacement right ?)

75.4=9.45t , t is approximately 8s .

0=18.9+8a

a=-2.37 rad/s^2
 
All good! :approve:
 

Similar threads

Replies
26
Views
2K
  • · Replies 4 ·
Replies
4
Views
2K
Replies
10
Views
2K
Replies
8
Views
5K
  • · Replies 2 ·
Replies
2
Views
3K
Replies
3
Views
2K
  • · Replies 5 ·
Replies
5
Views
4K
  • · Replies 12 ·
Replies
12
Views
2K
Replies
30
Views
4K
Replies
4
Views
2K