Angular momentum about inconvenient pivot point

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SUMMARY

The discussion centers on calculating the angular momentum of a rod of length L and mass M, rotating with angular velocity w about its center of mass, specifically regarding a pivot point located 1/4L from one end of the rod. The angular momentum with respect to the center of mass is defined as L = Iw = (1/12)ML²w. The parallel axis theorem is applicable for calculating the moment of inertia when determining angular momentum about a point that is not the center of mass.

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  • Understanding of angular momentum and its formulas
  • Familiarity with the parallel axis theorem
  • Knowledge of moment of inertia calculations
  • Basic principles of rotational dynamics
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  • Learn about calculating moment of inertia for different shapes
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kittyset
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A rod of length L and mass M is rotating with angular velocity w about its center of mass. What is its angular momentum with respect to a rotating point 1/4L from the rod's end? What about a stationary point?

Homework Equations


With the respect to the center of mass, angular momentum L = Iw = 1/12ML^2*w. (and L = r*Mv)

The Attempt at a Solution


Since the rod isn't actually rotating around the point (at least that's what I'm visualizing), does the parallel axis theorem still apply? How would calculation of moment of inertia work?
 
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It is actually rotating for given point I think and the parallel axis theorem can be applied for your calculation.
 

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