Angular Momentum and Average Torque

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Angular momentum is conserved overall, but the angular momentum of the specific rod in question is not conserved due to changes in its angular velocity. The initial angular momentum is 7.87, and the final angular momentum must be recalculated based on the rod's change in angular velocity from 0 to 26.03 over 7 seconds. Average torque is determined by the change in angular momentum divided by the change in time, which is not zero in this case. To find the average angular acceleration, standard constant acceleration equations should be applied. Understanding these concepts is crucial for correctly calculating average torque.
mohabitar
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Refer to number 6. This is the one I'm stuck on. So angular momentum is conserved right, so initial angular momentum is equal to final angular momentum. Initial is 7.87 so final must be 7.87, right? And so average torque is just change in angular momentum / change in time, so 0/7=0. What am I doing wrong?
 
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hi mohabitar! :smile:
mohabitar said:
… So angular momentum is conserved right, so initial angular momentum is equal to final angular momentum. Initial is 7.87 so final must be 7.87, right? And so average torque is just change in angular momentum / change in time, so 0/7=0.

no, total angular momentum is conserved, but the angular momentum of the rod isn't …

the angular velocity of the rod changes from 0 to 26.03 in 7 s …

so use one of the standard constant acceleration equations to find the (average) angular acceleration :wink:
 
The book claims the answer is that all the magnitudes are the same because "the gravitational force on the penguin is the same". I'm having trouble understanding this. I thought the buoyant force was equal to the weight of the fluid displaced. Weight depends on mass which depends on density. Therefore, due to the differing densities the buoyant force will be different in each case? Is this incorrect?

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