Angular momentum of a particle problem

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SUMMARY

The discussion focuses on the angular momentum of two identical particles with equal and opposite momenta, p and -p, not traveling along the same line. It establishes that the total angular momentum, calculated using the formula L = r x p, remains invariant regardless of the choice of origin. The participants emphasize that when the origin is shifted, the position vectors r1 and r2 adjust accordingly, yet the total angular momentum remains unchanged, demonstrating the principle of conservation of angular momentum in a system of particles.

PREREQUISITES
  • Understanding of angular momentum and its mathematical representation (L = r x p).
  • Familiarity with vector operations, specifically cross products.
  • Knowledge of the principle of conservation of angular momentum.
  • Basic grasp of torque and its relationship to angular momentum (Sum of torque = dL/dt).
NEXT STEPS
  • Study the implications of shifting the origin in angular momentum calculations.
  • Explore examples of angular momentum conservation in multi-particle systems.
  • Learn about the role of torque in angular momentum dynamics.
  • Investigate the application of angular momentum in rotational motion problems.
USEFUL FOR

Students studying classical mechanics, physics educators, and anyone interested in understanding angular momentum principles in particle systems.

yuki_meiseki
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Homework Statement


Two identical particles have equal but opposite momenta, p and -p, but they are not traveling along the same line show that the total angular momentum of this system does not depend on the choice of origin.


Homework Equations


L=r x p
Sum of torque = dL/dt


The Attempt at a Solution


Do not understand the problem at all.
 
Physics news on Phys.org
Total angular momentum is r1xp+r2x(-p). If you change the origin, r1 changes to r1+d and r2 changes to r2+d. Conclusion?
 

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