Alpha Particle Scattering and angular momentum

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Homework Help Overview

The discussion revolves around proving that the direction of angular momentum (L) is constant for an alpha particle undergoing scattering due to a central force. The original poster attempts to connect the definition of angular momentum, L = r × p, with the properties of central forces.

Discussion Character

  • Conceptual clarification, Assumption checking, Mixed

Approaches and Questions Raised

  • Participants explore the relationship between torque and angular momentum, noting that since the force is central, the torque is zero, which implies that angular momentum is conserved. However, there is a focus on demonstrating the constancy of the direction of L specifically.

Discussion Status

Some participants suggest that if the angular momentum vector is constant, its direction must also be conserved. Others express uncertainty about how to explicitly show that the direction of L remains unchanged, indicating a need for further exploration of the definition of L in the context of central forces.

Contextual Notes

There is an emphasis on the requirement to demonstrate the direction of L's conservation without relying on the conclusion that L itself is constant. Participants are questioning the assumptions and definitions related to torque and angular momentum in this context.

brotherbobby
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Statement of the problem :

"Using the definition L = r ##\times## p, prove that the direction of L is constant for an alpha (##\alpha##) particle whose scattering is shown in the diagram below. "

alpha.png


Relevant equations :

We are aware that the scattering takes place via a central force F = F(r) ##\hat r##. Angular momentum L = r ##\times## p and torque ##\tau = r \times F## (all vectors)The attempt at a solution

I can solve the problem, but not the way it asks. The torque ##\tau = r \times F \Rightarrow \tau = 0## since the force is central : F = F(r) ##\hat r##. Using ##\tau = \frac{dL}{dt} = 0##, inplies that the angular momentum vector L is constant.

[This is not what the question asks for. It asks to show only the direction of L conserved, from the definition of L : L = r ##\times## p].
 

Attachments

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If the vector itself is constant, then its direction must be conserved too ...

Also, where do you think ##\vec \tau = \vec r \times \vec F## comes from? :rolleyes:
 
Orodruin said:
If the vector itself is constant, then its direction must be conserved too ...
Yes, in that sense I have answered the question, but as I said, not in the way they asked for. I suppose they want one to focus on the direction of L and show that it remains the same.
Orodruin said:
Also, where do you think →τ=→r×→Fτ→=r→×F→\vec \tau = \vec r \times \vec F comes from?
I don't know. Torque and angular momentum are definitions, defined as the cross product of the radius vector and the force or the linear momentum, respectively.
 
brotherbobby said:
Torque and angular momentum are definitions, defined as the cross product of the radius vector and the force or the linear momentum, respectively.
So you need to relate those two, which you are going to do by computing the time derivative of the angular momentum.
 
Orodruin said:
So you need to relate those two, which you are going to do by computing the time derivative of the angular momentum.
All I am aware of is the standard : ##\frac{dL}{dt} = \frac{d}{dt}(r \times p) = r \times \frac{dp}{dt} = r \times F##.

It is this that I used to answer why the angular momentum L is constant - viz. the thrque is 0 owing to the fact that the force is central and hence L remains the same.

But the question asks me to show that the direction of L is a constant for a central force like this. (I am aware that I have already shown this in the form of the vector L itself being a constant).

I wonder if there is another way.

For instance, a vector L = ##L\hat L##. Can we show that ##\hat L## is a constant from the definition of L ( = ##r \times p##) for a central force (F(r))?
 

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