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Angular Momentum of a system of particles

  1. Apr 13, 2008 #1
    1. The problem statement, all variables and given/known data

    Two particles move in opposite directions along a straight line. Prticle 1 of mass m1 = 26kg at x1 = 23 m moves with a speed v1 = 43 m/s(to the right), while the particle 2 of mass m2 = 63 kg at x2= -22 m moves with a speed of -37 m/s(to the left).
    Given: Counter clockwise is the positive angular diretion.

    what is the total angular momentum of the system about the z-axis relative to point A along y axis if A is at (0,-17m)?


    2. Relevant equations

    Lsystem=L1+L2
    L=rXp
    p=mv




    3. The attempt at a solution

    the angular momentum about A for particle 1 would be 17X(26)(43) which would be clockwise making a negative L so L1=-19006kgm^2/s
    for particle2 it would be 17X(63)(37) counter clockwise spin about A so L2= 39627
    L1+L2= 20621, but this does not seem to be correct
     
  2. jcsd
  3. Apr 14, 2008 #2
    the 2 particles are located on the x-axis if that helps at all
     
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