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## Homework Statement

A thin uniform rod of length 0.810 m and mass M rotates horizontally at angular speed 21.0 rad/s about an axis through its center. A particle of mass M/3.00 attached to one end is ejected from the rod and travels along a path that is perpendicular to the rod at the instant of ejection. If the particle's speed vp is 6.00 m/s greater than the speed of the end of the rod just after ejection, what is the value of vp?

## Homework Equations

Li = Lf

L = IW

1/12 * m * r^2 = I for a rod rotating about its center

mvr* sin(angle between r and v) = I for particle

## The Attempt at a Solution

(1/12) * M * (.81^2) * 21rad/s = [1/12 * M * (.81^2)]W + [1/3*M * r * v]

so the problem is I have one equation with two unknowns, and no other equations....

(I tried to use that v = Wr, but I think that only works for rolling things and the answer didn't work out...)

Any help would be great! Thanks