Angular Momentum of Rotational Dynamics System

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Homework Help Overview

The problem involves calculating the angular momentum of a rotational dynamics system consisting of a thin rigid rod with point masses attached at both ends. The rod's dimensions and mass, as well as the angular velocity, are provided.

Discussion Character

  • Conceptual clarification, Assumption checking

Approaches and Questions Raised

  • Participants discuss the definition of the "physical center" of the rod and whether it refers to the center of mass or the midpoint. There is also mention of the need to consider the contributions of the point masses to the moment of inertia.

Discussion Status

The discussion is exploring the interpretation of the problem's terms and the necessary components for calculating the moment of inertia. Participants are questioning assumptions about the setup and clarifying the role of the point masses in the calculations.

Contextual Notes

There is an emphasis on the contributions of the point masses to the overall moment of inertia, indicating that the original poster's approach may need adjustment based on these considerations.

linnus
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Homework Statement



0.14 meter long, 0.15 kg thin rigid rod has a small 0.22 kg mass stuck on one of its ends and a small 0.080 kg mass stuck on the other end. The rod rotates at 1.7 rad/s through its physical center without friction. What is the magnitude of the angular momentum of the system taking the center of the rod as the origin? Treat the masses on the ends as point masses.

Homework Equations



I= summation of mr^2
I=1/12mL^2 (for the rod)
L=IW

The Attempt at a Solution


I=1/12(.45)(.14^2)= .000735
L=.000735 (1.7)=.0012495 kgm/s^2
 
Last edited:
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physical center? is that center of mass or something? or midway of rod?

there is contribution from the small masses to moment of inertia
 
I think it means the midway of the rod.
 
either way you will need to include the two point masses at the two ends
 

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