Angular Momentum of Rotational Dynamics System

linnus
Messages
22
Reaction score
0

Homework Statement



0.14 meter long, 0.15 kg thin rigid rod has a small 0.22 kg mass stuck on one of its ends and a small 0.080 kg mass stuck on the other end. The rod rotates at 1.7 rad/s through its physical center without friction. What is the magnitude of the angular momentum of the system taking the center of the rod as the origin? Treat the masses on the ends as point masses.

Homework Equations



I= summation of mr^2
I=1/12mL^2 (for the rod)
L=IW

The Attempt at a Solution


I=1/12(.45)(.14^2)= .000735
L=.000735 (1.7)=.0012495 kgm/s^2
 
Last edited:
Physics news on Phys.org
physical center? is that center of mass or something? or midway of rod?

there is contribution from the small masses to moment of inertia
 
I think it means the midway of the rod.
 
either way you will need to include the two point masses at the two ends
 

Similar threads

  • · Replies 71 ·
3
Replies
71
Views
5K
  • · Replies 4 ·
Replies
4
Views
2K
  • · Replies 2 ·
Replies
2
Views
2K
  • · Replies 19 ·
Replies
19
Views
5K
Replies
5
Views
2K
Replies
67
Views
5K
Replies
10
Views
3K
  • · Replies 8 ·
Replies
8
Views
2K
Replies
335
Views
19K
  • · Replies 17 ·
Replies
17
Views
2K