Angular Momentum of Rotational Dynamics System

AI Thread Summary
The discussion revolves around calculating the angular momentum of a rotational dynamics system involving a thin rigid rod and two point masses. The rod is 0.14 meters long and has a mass of 0.15 kg, with additional masses of 0.22 kg and 0.080 kg attached at each end. The angular momentum is derived using the moment of inertia, calculated as I=1/12mL^2 for the rod, and incorporating the contributions from the point masses. The initial calculation of I was noted as .000735, leading to an angular momentum L of approximately .0012495 kgm/s. Clarification is sought on whether the center of rotation refers to the physical center or the center of mass of the system.
linnus
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Homework Statement



0.14 meter long, 0.15 kg thin rigid rod has a small 0.22 kg mass stuck on one of its ends and a small 0.080 kg mass stuck on the other end. The rod rotates at 1.7 rad/s through its physical center without friction. What is the magnitude of the angular momentum of the system taking the center of the rod as the origin? Treat the masses on the ends as point masses.

Homework Equations



I= summation of mr^2
I=1/12mL^2 (for the rod)
L=IW

The Attempt at a Solution


I=1/12(.45)(.14^2)= .000735
L=.000735 (1.7)=.0012495 kgm/s^2
 
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physical center? is that center of mass or something? or midway of rod?

there is contribution from the small masses to moment of inertia
 
I think it means the midway of the rod.
 
either way you will need to include the two point masses at the two ends
 
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