Angular momentum operators and eigenfunctions

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The discussion focuses on the evaluation of angular momentum operators and their eigenfunctions, specifically Lz. The first wavefunction, labeled as Ψ0, is confirmed to have an eigenvalue of zero due to its symmetry under rotations, indicating no angular momentum. For the second wavefunction, Ψ1, it is suggested to demonstrate that it does not satisfy the eigenvalue equation by showing that the left-hand side results in zero while the right-hand side yields a nonzero value. Additionally, there is confusion about converting wavefunctions into spherical polar coordinates, with clarification that the exercise requires both the operator's cross product and the wavefunctions. Overall, the conversation emphasizes the importance of understanding the properties of wavefunctions in relation to angular momentum.
machofan
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Homework Statement



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Homework Equations


The Attempt at a Solution



I have tried inserting the first wavefunction into Lz which gets me 0 for the eigenvalue for the first wavefunction. Is this correct?

For the second wavefunction, I inserted it into Lz and this gets me -i*hbar*xAe^-r/a which is not equal to an eigenvalue*Ay*e-r/a, although I am not sure if this is the correct justification.

Any help is much appreciated, thank you.
 
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Seems right to me.
 
I'm also stuck on how to convert the wavefunctions into spherical polar coordinates, having tried to use the formula for spherical polar coordinates, I notice that the wavefunctions do not depend on the variables phi and theta, so I am unsure on how to approach the first problem.
 
Hello fan, and welcome to PF.

You get 0 for ##\Psi_0## because it is symmetric under rotations around the z axis: there is no angular momentum. So I think you are right. It is an eigenfunction.

For ##\Psi_1## you basically want to show that ##{\bf L}_z \left( \Psi_1 \right ) = L_z\, \Psi_1 ## with ##{\bf L}_z## the operator and ##L_z## an eigenvalue (i.e. a number, possibly complex), has no solutions.

You may assume |A| is not equal to zero (because of the normalization) so the eigenvalue zero is already excluded. So if you multiply the right hand side from the left by ##\Psi_1^*## and integrate, that yields ##L_z##, which is nonzero.

Do the same thing with the lefthand side and show that it does give zero. That way you prove that the assumption that ##\Psi_1## is an eigenfunction leads to a false equation.
 
machofan said:
I'm also stuck on how to convert the wavefunctions into spherical polar coordinates, having tried to use the formula for spherical polar coordinates, I notice that the wavefunctions do not depend on the variables phi and theta, so I am unsure on how to approach the first problem.
With ##z = r\cos\theta## you sure have a theta dependence!
 
But the exercise wants you to write out the z-component of the operator cross product ##{\bf r} \times {\bf p}##, not the wave functions!
[edit] sorry, it wants you to do both. In the first part the Lz, later on the ##\Psi##
 
BvU said:
Hello fan, and welcome to PF.

You get 0 for ##\Psi_0## because it is symmetric under rotations around the z axis: there is no angular momentum. So I think you are right. It is an eigenfunction.

For ##\Psi_1## you basically want to show that ##{\bf L}_z \left( \Psi_1 \right ) = L_z\, \Psi_1 ## with ##{\bf L}_z## the operator and ##L_z## an eigenvalue (i.e. a number, possibly complex), has no solutions.

You may assume |A| is not equal to zero (because of the normalization) so the eigenvalue zero is already excluded. So if you multiply the right hand side from the left by ##\Psi_1^*## and integrate, that yields ##L_z##, which is nonzero.

Do the same thing with the lefthand side and show that it does give zero. That way you prove that the assumption that ##\Psi_1## is an eigenfunction leads to a false equation.

That has really cleared things up, thank you!
 
Last edited:

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