Angular momentum polar coordinates

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The discussion revolves around deriving the z component of angular momentum in polar coordinates, transitioning from the Cartesian definition. The operator is initially expressed as L_z = -ih[x(d/dy) - y(d/dx)] and needs to be reformulated to L_z = -ih(d/dθ). Participants express confusion over the derivation process, noting that previous examples typically involve spherical coordinates rather than polar. Suggestions include rewriting derivatives in terms of polar coordinates and using the identity that relates partial derivatives with respect to θ. The conversation emphasizes the challenge of transforming coordinate systems while maintaining clarity in the derivation.
johnnyies
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Homework Statement



from the cartesian definition of angular momentum, derive the operator for the z component in polar coordinates

L_z = -ih[x(d/dy) - y(d/dx)]

to

L_z = -ih(d/dθ)

Homework Equations


x = rcosθ
y = rsinθ

r^2 = x^2 + y^2

r = (x^2 + y^2)^1/2

The Attempt at a Solution



first of all I'm not sure how this is even possible. Every derivation of the angular momentum operator I've seen requires spherical coordinates, not polar.

I tried taking the derivative of r with respect to x to get cosθ and with respect to y to get sinθ

and dx/dθ = -rsinθ dy/dθ = rcosθ but it's not getting me anywhere.

is there something i should be rewriting d/dx and d/dy as?
 
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Since you are transforming from one basis to another, you can use the identity (written for your particular case):

\frac{∂}{∂θ} = \frac{∂x}{∂θ}\frac{∂}{∂x} + \frac{∂y}{∂θ}\frac{∂}{∂y}.

Does that help?
 

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