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Angular Momentum Problem of rod

  • Thread starter nateshoe
  • Start date
  • #1
9
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Homework Statement



A uniform rod of mass m_1 and length L rotates in a horizontal plane about a fixed axis through its center and perpendicular to the rod. Two small rings, each with mass m_2, are mounted so that they can slide along the rod. They are initially held by catches at positions a distance r on each side from the center of the rod, and the system is rotating at an angular velocity omega. Without otherwise changing the system, the catches are released, and the rings slide outward along the rod and fly off at the ends.

What is the angular speed of the rod after the rings leave it?


Homework Equations


I(rod)=(1/12)mL^2

I(ring)=mr^2

wf=wi*(Ii/If)


The Attempt at a Solution



wf=wi*((1/12*m1*L^2+2*m2*r^2)/(1/12*m1*L^2)


Nevermind I figured it out, it is the same concept as sand falling out of a moving truck.
 
Last edited:

Answers and Replies

  • #2
8
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Hmm I'm having trouble with this one. Could you lead me in the right direction?
 

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