Which Graph Best Represents the Stone's Angular Momentum Over Time?

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The discussion focuses on determining the correct graph that represents the angular momentum of a falling stone over time. The stone's angular momentum is defined as the cross product of its position vector and momentum, leading to the conclusion that angular momentum is linear in time. The key insight is that while both the position and angle change, the horizontal distance remains constant, making the momentum's vertical component the only variable affecting angular momentum. Participants explore different methods to intuitively understand the relationship between angular momentum and time without complex calculations. Ultimately, the consensus leans towards a linear relationship, suggesting that the graph representing angular momentum as a function of time is linear.
awvvu
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Homework Statement


A stone falls from rest from the top of a building. Which of the following graphs' shapes best represents the stone's angular momentum L about the point P as a function of time?

http://img413.imageshack.us/img413/1033/54161793ev0.png

a) L = 0
b) L = c (constant)
c) L = c * t (linear in t)
d) L = t^2
e) L = upside-down parabola with vertex at some positive x and positive y, passing through the origin

The Attempt at a Solution


I think I solved this problem using the definition of angular momentum as the cross product of r and p (calling point P (x_0, y_0)):

\vec{L} = \vec{r} \times \vec{p} = \left| \begin{array}{ccc}<br /> \hat{i} &amp; \hat{j} &amp; \hat{k} \\<br /> r_x &amp; r_y &amp; 0 \\<br /> 0 &amp; p_y &amp; 0 \end{array} \right| = r_x p_y \hat{k} = x_0 m g t \hat{k}

where r_x = x_0 and p_y = - m g t

So apparently linear momentum is linear in time. This question is for an AP Physics C sample multiple choice, so I have a hard time believing they want us to evaluate a cross-product to figure out this. Is there some intuitive way to understand this? Or a quick way to do it? I tried using the definition of cross product as r p \sin(\theta) but that doesn't get me very far either.
 
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Hi awvvu,

About your definition rp \sin(\theta), I think that is a good way to see it. If you think about the path of the stone as it falls (vertically), notice that r and theta both change with time, but r\sin\theta is a constant--it's just the horizontal distance from the point to the ball's path. So the only thing changing with time in rp \sin(\theta), is p.

There are also the slightly differently-written forms m v_{\perp} r and m v r_{\perp} for the angular momentum of a particle. The second form works best here: you know the velocity is vertical, so r_{\perp} must be the horizontal distance.
 
Ah, I was trying to look at each multiplied term separately and I couldn't figure out the relationship between r and sin(theta).
 
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