Angular resolution of microscope

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The discussion centers on the calculation of angular resolution in microscopy using the formula θ = 1.22λ/d. A user attempts to apply this formula with given values but arrives at a different answer than expected. Clarification is sought regarding the relationship between numerical aperture (NA) and the wavelength (λ) and diameter (d). Participants confirm the initial formula for theta is correct, suggesting a re-evaluation of the results. The conversation emphasizes the importance of accurately linking the concepts of NA, wavelength, and resolution in microscopy.
kenok1216
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Homework Statement


擷取1.PNG


Homework Equations


θ =1.22λ/d

The Attempt at a Solution


for (a) θ =1.22λ/d
θ =1.22(579nm)/(1.2cm)[/B]
θ =5.8865x10^-5 degree= 1.027x10^-6 rad but the answer =2x10^-3rad ,
for the micorscope, the formula of angular resolution is different?
i find that NA=nsina (but how can i link with λ and d?)
 
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kenok1216 said:
The attempt at a solution
for (a) θ =1.22λ/d
θ =1.22(579nm)/(1.2cm)
θ =5.8865x10^-5 degree= 1.027x10^-6 rad but the answer =2x10^-3rad ,
for the micorscope, the formula of angular resolution is different?
i find that NA=nsina (but how can i link with λ and d?)

your formula for theta seems to be correct -check the results once again.
 
drvrm said:
your formula for theta seems to be correct -check the results once again.
YES, it is right, the answer is 5.8865x10^-5 rad
 
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