Angular Velocity w/2 welded disks

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SUMMARY

The discussion centers on calculating the angular velocities of two concentric disks, one smaller (1.66 kg, radius 12.4 cm) and one larger (6.85 kg, radius 24.8 cm), when two identical masses (800 g each) are released from rest. The problem requires applying principles of rotational dynamics and energy conservation to determine the angular velocity of both disks and the linear velocity of the masses when they are 60.0 cm apart. The inertia formulas for both disks are given as I = 1/2 m R², which are crucial for solving the problem.

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Homework Statement



Two concentric disks attached to each other form a single unit. This two disk unit is mounted onto a frictionless horizontal axle through the center hole. Two strings are attached and wound in opposite directions around the outer perimeter of each disk and are left hanging. The smaller disk has a mass of 1.66 kg and a radius R1 of 12.4 cm. The larger disk has a mass of 6.85 kg and a radius R2 of 24.8 cm. (a) If two identical masses of 800 g are hung from both strings and the two masses are released from rest from the same initial height what will be the angular velocity of the larger disk when the two masses are 60.0 cm apart? What will be the angular velocity of the smaller disk and the linear velocity of each mass at the same instant? (Figure 3)


Homework Equations





The Attempt at a Solution



well I'll write down all the variables given

*smaller* *larger* *mass1* *mass2*
r1 = 12.4cm r2 = 24.8cm m1 = 800g m2 = 800g
m1 = 1.66kg m2 = 6.85kg


what we want is ω of larger disk, ω of smaller disk, and V_f of each mass

Im not really sure where to get started here.

Inertia of smaller disk = 1/2mR²
Inertia of larger disk = 1/2mR²


any hints here?
 
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You can either use dynamics (applying Newton's 2nd law to all three objects) or energy conservation.
 

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