If I have a triangle diagram for [itex]Z \rightarrow W^-W^+[/itex], do all fermions contribute the same for giving the contraint [itex]\sum_i Q_i =0[/itex]??(adsbygoogle = window.adsbygoogle || []).push({});

I think that eg top quarks will be absent for such a diagram......

any help?

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# Anomaly cancellation triangle

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