Probability of at Least One Girl in a Five-Child Family | Independent Births

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The discussion centers on calculating the probability of a family with five children having at least one girl, given that they have at least one boy. The initial calculation presented was 15/16, but the correct answer is 30/31. The confusion arises from the need to apply conditional probability, considering only scenarios where there is at least one boy. The key is to exclude the combinations of all boys or all girls when calculating the probability. The problem emphasizes understanding binomial distribution and conditional probability to arrive at the correct solution.
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Hi
I have some difficulties with following question.

A family has five children. Assuming that the probability of a girl on each birth was 1/2 and that the five births were independent, what is the probability the family has at least one girl, given they have at least one boy?

My solution is 1-(1/2)^4 = 15/16

However according to the book correct answer it 30/31.
Any ideas?
 
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tramp said:
Hi
I have some difficulties with following question.

A family has five children. Assuming that the probability of a girl on each birth was 1/2 and that the five births were independent, what is the probability the family has at least one girl, given they have at least one boy?

My solution is 1-(1/2)^4 = 15/16

However according to the book correct answer it 30/31.
Any ideas?

Look at material on the binomial distribution.

The conditions in the problem are satisified if the family has any of the following combinations of genders:
(exactly 1 boy and 4 girls)
(exactly 2 boys and 3 girls)
(exactly 3 boys and 2 girls)
(exactly 4 boys and 1 girl)

The conditions are not satisfied by the combinations of genders:
(exactly 5 boys and 0 girls )
(exactly 0 boys and 5 girls )

The problem says we are "given" that the family has at least one boy, so you should look at the formula for conditional probability.
 
Thanks a lot Stephen.
I figured it out. Your post was a great help.
 
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