- #1

haydn

- 27

- 0

## Homework Statement

Sketch the region enclosed by the given curves. Decide whether to integrate with respect to x or y. Then find the area of the region.

x+y^2=6

x+y=0

## Homework Equations

none, just using integrals...

## The Attempt at a Solution

I sketch the two curves and find they intersect at x=-3 and x=2. Looking at it I want to integrate with respect to x.

y=[tex]\sqrt{-x+6}[/tex] appears to be the top function, while y=-x is the lower function.

I set up an integral from -3 to 2 that consists of: [tex]\sqrt{-x+6}[/tex] - (-x) dx.

I evaluate using substitution and keep getting 10.16, which the homework website I'm using says is wrong. Not sure what I'm doing incorrectly here.