Another pulley problem (answer check)

[Lori]

Homework Statement

Homework Equations

Shown above

The Attempt at a Solution

Shown above.

Since the normal force is just the force opposite to the surface (gravity force) , it's just mgcos(theta).
[/B]

 

[haruspex]

The option you selected has mass (m) on the left but forces (mg) on the right.

 

[Lori]

The option you selected has mass (m) on the left but forces (mg) on the right.

isnt the answer just the left horizontal forces? so friction + horizontal component force from gravity

 

[haruspex]

isnt the answer just the left horizontal forces? so friction + horizontal component force from gravity

Please try to understand what I wrote. The option you selected makes no sense dimensionally. It does not mean anything to say that a mass is more or less than a force.

 

[Lori]

Please try to understand what I wrote. The option you selected makes no sense dimensionally. It does not mean anything to say that a mass is more or less than a force.

Ohhh. I just need to remove the g by dividing to get it in mass . So option a

 

[haruspex]

Ohhh. I just need to remove the g by dividing to get it in mass . So option a

Right.