Another pulley problem (answer check)

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Homework Help Overview

The discussion revolves around a pulley problem involving forces, mass, and the normal force in a physics context. Participants are examining the relationships between different forces acting on a mass and questioning the dimensional consistency of the selected options.

Discussion Character

  • Conceptual clarification, Assumption checking, Problem interpretation

Approaches and Questions Raised

  • Participants are attempting to clarify the relationship between mass and forces in the context of the problem. There are questions about the dimensional consistency of the selected options and whether the answer should focus solely on horizontal forces, including friction and the horizontal component of gravity.

Discussion Status

There is an ongoing exploration of the dimensional aspects of the options presented. Some participants are providing guidance on how to approach the problem, while others are questioning the validity of the selected options. Multiple interpretations of the problem are being discussed.

Contextual Notes

Participants are grappling with the implications of dimensional analysis in their selections and the definitions of forces versus mass in the context of the problem. There is an indication of confusion regarding the relationship between gravitational force and mass in the equations being considered.

Lori

Homework Statement


upload_2017-11-8_14-29-34.png


Homework Equations


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The Attempt at a Solution



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Since the normal force is just the force opposite to the surface (gravity force) , it's just mgcos(theta).
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The option you selected has mass (m) on the left but forces (mg) on the right.
 
haruspex said:
The option you selected has mass (m) on the left but forces (mg) on the right.
isnt the answer just the left horizontal forces? so friction + horizontal component force from gravity
 
Lori said:
isnt the answer just the left horizontal forces? so friction + horizontal component force from gravity
Please try to understand what I wrote. The option you selected makes no sense dimensionally. It does not mean anything to say that a mass is more or less than a force.
 
haruspex said:
Please try to understand what I wrote. The option you selected makes no sense dimensionally. It does not mean anything to say that a mass is more or less than a force.
Ohhh. I just need to remove the g by dividing to get it in mass . So option a
 
Lori said:
Ohhh. I just need to remove the g by dividing to get it in mass . So option a
Right.
 

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