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Another Q about double-slit experiment

  1. Apr 17, 2007 #1
    1. The problem statement, all variables and given/known data
    Youngs double-slit experiment is performed with 589nm light and a distance of 2.00m between the slits and the screen. The tenth interference minimum is observed 7.26mm from the central maximum. Determine the spacing on the slits.

    2. Relevant equations
    Iavg = (Imax) cos^2 [(pi d sin angle) / lambda]
    (it is very frustrating not being able to insert relevent symbols :grumpy: )

    3. The attempt at a solution
  2. jcsd
  3. Apr 17, 2007 #2
    hm you seem to be using the wrong formula, in this case we are not measuring the intensity but using: distance from central max= (wavelength * distance to screen*order number)/spacing of slits. Hoped that helped
  4. Apr 17, 2007 #3
    589nm x 2.00m x 10 / .00726m = spacing of slits

    1622589m between slits?
  5. Apr 17, 2007 #4
    Sorry to change the topic, but look here for some info on LaTeX https://www.physicsforums.com/showthread.php?t=8997 if you want to make the equations look right
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