Another Q about double-slit experiment

AI Thread Summary
The discussion revolves around calculating the spacing between slits in Young's double-slit experiment using given parameters. The relevant formula for determining the distance from the central maximum is highlighted, which involves the wavelength, distance to the screen, and the order number. A participant suggests using the formula to find the slit spacing, leading to a calculation that results in a spacing of approximately 1622589 meters. Additionally, there is a side note about the difficulty of inserting symbols in the discussion, with a suggestion to use LaTeX for better formatting. The conversation emphasizes the importance of using the correct formula for accurate results in physics problems.
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Homework Statement


Youngs double-slit experiment is performed with 589nm light and a distance of 2.00m between the slits and the screen. The tenth interference minimum is observed 7.26mm from the central maximum. Determine the spacing on the slits.

Homework Equations


Iavg = (Imax) cos^2 [(pi d sin angle) / lambda]
(it is very frustrating not being able to insert relevant symbols )

The Attempt at a Solution


?
 
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hm you seem to be using the wrong formula, in this case we are not measuring the intensity but using: distance from central max= (wavelength * distance to screen*order number)/spacing of slits. Hoped that helped
 
589nm x 2.00m x 10 / .00726m = spacing of slits

1622589m between slits?
 
aquabum619 said:

Homework Statement


Iavg = (Imax) cos^2 [(pi d sin angle) / lambda]
(it is very frustrating not being able to insert relevant symbols )

Sorry to change the topic, but look here for some info on LaTeX https://www.physicsforums.com/showthread.php?t=8997 if you want to make the equations look right
 
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