Another Vector question Quick one!

  • Thread starter prace
  • Start date
  • #1
102
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So I am given this:

If l has parametric equations

x = 5-3t
y = -2+t
z = 1+9t

find parametic equations for the line through P(-6,4,-3) that is parallel to l.

So, my question is this: for the two lines to be parallel, they have to have the same direction vector right? In this case, <-3, 1, 9>. So if I were to find the parallel line to l, it would be:

x = -6-3s
y = 4+s
z = -3+9s

Thanks!!
 

Answers and Replies

  • #3
102
0
Awesome!! Thank you!
 

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