Another Vector question Quick one

[prace]

So I am given this:

If l has parametric equations

x = 5-3t
y = -2+t
z = 1+9t

find parametic equations for the line through P(-6,4,-3) that is parallel to l.

So, my question is this: for the two lines to be parallel, they have to have the same direction vector right? In this case, <-3, 1, 9>. So if I were to find the parallel line to l, it would be:

x = -6-3s
y = 4+s
z = -3+9s

Thanks!

 

[benorin]

Your absolutely correct!

 

[prace]

Awesome! Thank you!