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Another Vector question Quick one!

  1. Oct 29, 2006 #1
    So I am given this:

    If l has parametric equations

    x = 5-3t
    y = -2+t
    z = 1+9t

    find parametic equations for the line through P(-6,4,-3) that is parallel to l.

    So, my question is this: for the two lines to be parallel, they have to have the same direction vector right? In this case, <-3, 1, 9>. So if I were to find the parallel line to l, it would be:

    x = -6-3s
    y = 4+s
    z = -3+9s

  2. jcsd
  3. Oct 30, 2006 #2


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    Homework Helper

    Your absolutely correct!
  4. Oct 30, 2006 #3
    Awesome!! Thank you!
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