This is not homework but it is more practise for me. We have to find the derivative of f(x) = sqrt(2x + 5) using the definition of a derivative, I used to remember how to do this but now I am not able to figure out what I am doing wrong.(adsbygoogle = window.adsbygoogle || []).push({});

Here is what I have.

y' = lim(h -> 0) [sqrt(2{x + h} + 5) - sqrt(2x + 5)] / h

y' = (lim(h -> 0) [sqrt(2{x + h} + 5) - sqrt(2x + 5)] / h) * ([sqrt(2{x + h} + 5) + sqrt(2x + 5)] / [sqrt(2{x + h} + 5) + sqrt(2x + 5)])

y' = lim(h -> 0) [2(x + h) + 5 - (2x + 5)] / h[sqrt(2{x + h} + 5) - sqrt(2x + 5)]

y' = lim(h-> 0) [2x + 2h + 5 - 2x - 5] / h[sqrt(2{x + h} + 5) - sqrt(2x + 5)]

y' = lim(h ->0) 2h / h[sqrt(2{x + h} + 5) - sqrt(2x + 5)]

y' = lim(h->0) 2 / [sqrt(2{x + h} + 5) - sqrt(2x + 5)]

I have no idea how to format the questions to make them look nice.

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# Homework Help: Another, what should be simple, derivative question

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